If you mean: 3x+2y+6 = 0 then it is y = -1.5x-3 as a straight line equation
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3x+2y-5=0 3x+2y=5 Im lost im only 12 work out the rest hope i helped
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
3xy-2y=0 3xy=2y y=2y (3x) y/2y=3x 1/2=3x multiply across by 2 1=6x 1/6=x therefore substituting x=1/6 into 3xy-2y; 3(1/6)y-2y=0 1/2y=2y y=2y/0.5 0.5 aka 1/2 y=1
x+2y=8 Here you must add the expressions (2y - 2y = 0) 3x-2y=8 4x=16 Now you are left with a multiple of x so you can simply divide by 4 x=4 on both sides of the = 4+2y=8 Now you substitute x=4 into one of the original equations to find y 2y=4 y=2 Hope this helped.
No, it has an infinite number of solutions. The coordinates of each and every point on the line 3x + 2y + 4 = 0 is a solution.