The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
4y -2 = 6 4y = 6 + 2 4y = 8 y = 2
5x - 4y ≥ -203x - 2y ≤ -8y ≥ -3
6(y - 4)
2x - 3y = -4x + 4y = -9from the second equation x = -9-4y , substitute it in the first equation.2(-9-4y)- 3y= -4-18-8y-3y = -4-18-11y = -4-11y = -4+18-11y = 14y = -14/11now, solve for x :x = -9-4yx = -9-4(-14/11)x = -43/11
4y+2 = 2y+6 4y-2y = 6-2 2y = 4 y = 2
2
You can't solve it. But you can simplify it to get: 4x+y=2
The answer to x2 - 2x - 4y2 - 4y =(x - 2y)(x - 2y - 2)
How do you solve 4y plus x equals 8
The equation 4y = 2x + 2 cannot just be solved. If you are trying to solve a system, you need as many equations as you have variables (x and y in this case). Since you have two variables, you need two equations.For example, if you had:4y = 2x + 2 AND 2y = 4x + 4, then it would be possible to solve like so....first solve for one of the variables in one of the equations. Let's go for y in the second equation.2y = 4x + 4 ----> 2y/2 = 4x/2 + 4/2 ----> y = 2x + 2.now use this value of y and place it into the first equation and then you can solve for x.4(2x + 2) = 2x + 2 ----> 8x + 8 = 2x + 2 ----> 6x = -6 ----> x = -1now you can replace the -1 into either equation and solve for y4y = 2(-1) + 2 ----> 4y = -2 + 2 ----> 4y = 0 ----> y = 0So, if there is another equation for you to solve with, you can easily use this method to solve for both variables.
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
- 8Y5===- 8 is the coefficient.The term is in the fifth degree.The Y, of course, is the variable base.
Assume the expression is x = 40 - 4y, and assume we want to solve for y. Rearrange the terms to get: x - 40 = -4y y = -¼(x - 40)
If you mean: 4y^2 +3 -13y then the expression is (4y-1)(y-3) when factored
2y = 4x + 4y = 2x + 2
4y + 7 = 19 ∴ 4y = 12 ∴ y = 3