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You can't solve this since it isn't an equation.
There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?
Restate the question: Simplify log(x3)
Answer: 3log(x)
You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
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How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
How do you solve x3 plus 4x2 plus 6x plus 24?
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
How do you solve 1-x3 by factoring?
-(x - 1)(x2 + x + 1)
How do you solve 1-x3?
1-3x1=3x 1/3=x
If 3 log x - 2 log y?
1
How do you solve a log?
You calculate a log, you do not solve a log!
How do you find cube of a number using log?
If log(x) = y then log(x3) = 3*log(x) = 3*y so that x3 = antilog(3*y) So, to find the cibe of x 1) find log x 2) multiply it by 3 3) take the antilog of the result.
How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
How do you solve the equation Factorise x3 4x?
X(X2 - X)
How do you solve x3 plus 4x2 plus 6x plus 24?
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
How do you solve 1-x3 by factoring?
-(x - 1)(x2 + x + 1)
How do you solve 1-x3?
1-3x1=3x 1/3=x
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
How do you solve x5 equals 64x2?
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
How do you solve X3 equals 216?
cube root of 216 = 6 > X= 6
