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You can't solve this since it isn't an equation.
There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?
Restate the question: Simplify log(x3)
Answer: 3log(x)
You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
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How do you solve this inequality x3 6x2-x-30 Show work for x?
x3 6x2-x-30
How do you solve x3 plus 4x2 plus 6x plus 24?
x3 + 4x2 + 6x + 24 = (x2 + 6)(x + 4)
How do you solve 1-x3 by factoring?
-(x - 1)(x2 + x + 1)
How do you solve 1-x3?
1-3x1=3x 1/3=x
How do you solve x-1 plus x2-x plus x3-x2 plus x4-x3?
x4 - 1.We can not "solve" this as we have not been told the value of x. However, we can simplify this expression:We have an x and a minus x here which will cancel out. Likewise the x2 and x3 will cancel out with the -x2 and -x3 respectively. This therefore leaves us with just x4 - 1.
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