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How do you solve log x plus log 8 equals 1?
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
I need to evaluate the following logarithm log base 8 of the cube root of 1by2.Plz solve?
The part we don't understand is: If you need to evaluate it, then why do we need to solve it ?Here's a suggestion on how to go about it:log8(0.51/3) = 1/3 log8(0.5)To find log8(0.5) : let's call it 'Q'8Q = 0.5Q log(8) = log(0.5)Q = log(0.5) / log(8)Now you can find 'Q', and then 1/3 of Q is the answer to your original question.
What is log10 - log 8?
The expression ( \log_{10} - \log 8 ) can be simplified using the logarithmic property that states ( \log a - \log b = \log \left( \frac{a}{b} \right) ). Therefore, ( \log_{10} - \log 8 = \log \left( \frac{10}{8} \right) ) or ( \log \left( 1.25 \right) ). This represents the logarithm of 1.25 to the base 10.
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve log x3?
You can't solve this since it isn't an equation.There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?Restate the question: Simplify log(x3)Answer: 3log(x)You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
