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How do you solve log x plus log 8 equals 1?
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
I need to evaluate the following logarithm log base 8 of the cube root of 1by2.Plz solve?
The part we don't understand is: If you need to evaluate it, then why do we need to solve it ?Here's a suggestion on how to go about it:log8(0.51/3) = 1/3 log8(0.5)To find log8(0.5) : let's call it 'Q'8Q = 0.5Q log(8) = log(0.5)Q = log(0.5) / log(8)Now you can find 'Q', and then 1/3 of Q is the answer to your original question.
What is log10 - log 8?
The expression ( \log_{10} - \log 8 ) can be simplified using the logarithmic property that states ( \log a - \log b = \log \left( \frac{a}{b} \right) ). Therefore, ( \log_{10} - \log 8 = \log \left( \frac{10}{8} \right) ) or ( \log \left( 1.25 \right) ). This represents the logarithm of 1.25 to the base 10.
How do you solve Log3 log2x - log(3x plus 7)?
To solve the equation ( \log_3(\log_2 x) - \log(3x + 7) = 0 ), first rewrite it as ( \log_3(\log_2 x) = \log(3x + 7) ). This implies ( \log_2 x = 3^{\log(3x + 7)} ). Next, convert ( \log(3x + 7) ) to base 3, and isolate ( x ) by converting back to exponential form. Finally, solve the resulting equation for ( x ).
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve a log?
You calculate a log, you do not solve a log!
How do you solve 3 log of 8 equals x?
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
How do you solve log x plus log 8 equals 1?
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
I need to evaluate the following logarithm log base 8 of the cube root of 1by2.Plz solve?
The part we don't understand is: If you need to evaluate it, then why do we need to solve it ?Here's a suggestion on how to go about it:log8(0.51/3) = 1/3 log8(0.5)To find log8(0.5) : let's call it 'Q'8Q = 0.5Q log(8) = log(0.5)Q = log(0.5) / log(8)Now you can find 'Q', and then 1/3 of Q is the answer to your original question.
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
Which expressions are equivalent to log 2 - log 8?
-6
What is 8(5 to the power of x) equal 23?
8 × 5^x = 23 → 5^x = 2.875 → x log 5 = log 2.875 → x = log 2.875 ÷ log 5 (You can use logs to any base as long as the same base is used for both of the logs.)
What does x equals in 2 log x equals log 8?
2 log(x) = log(8)log(x2) = log(8)x2 = 8x = sqrt(8) = 2.82843 (rounded)Note that only the positive square root of 8 can serve as a solution to thegiven equation, since there's no such thing as the log of a negative number.
How can you solve 5 idices n equal 8 how can i find n when it appears as indice?
I understand this to mean 5n = 8 We try to convert equations like these into equations involving logarithms. Which is fairly easy. In the usual way that we might add constants to both sides of an equation of take square roots of both sides, let us just take logarithms of both sides of this one. n log 5 = log 8 (the logarithm of the power of a number is the product of the log of the number and the power) Then n = log 8 / log 5 ~= 1.29
What is log10 - log 8?
The expression ( \log_{10} - \log 8 ) can be simplified using the logarithmic property that states ( \log a - \log b = \log \left( \frac{a}{b} \right) ). Therefore, ( \log_{10} - \log 8 = \log \left( \frac{10}{8} \right) ) or ( \log \left( 1.25 \right) ). This represents the logarithm of 1.25 to the base 10.
How do you solve for a power in a math problem?
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
What is 8 log base 8 of 19?
The expression 8 log base 8 of 19 can be rewritten as log base 8 of 19 raised to the 8th power. This is because the logarithm function is the inverse of the exponentiation function. Therefore, 8 log base 8 of 19 simplifies to log base 8 of 19^8.
