0
Add your answer:
Earn +20 pts
How do you solve log x plus log 8 equals 1?
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
I need to evaluate the following logarithm log base 8 of the cube root of 1by2.Plz solve?
The part we don't understand is: If you need to evaluate it, then why do we need to solve it ?Here's a suggestion on how to go about it:log8(0.51/3) = 1/3 log8(0.5)To find log8(0.5) : let's call it 'Q'8Q = 0.5Q log(8) = log(0.5)Q = log(0.5) / log(8)Now you can find 'Q', and then 1/3 of Q is the answer to your original question.
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
How do you solve 3log5 125 - log2 8 equals x?
Your calculator won't usually have a function to calculate logs in base 5 or base 8 directly, but this can easily be solved. For example: log5125 = log 125 / log 5 (taking both logs in base 10, or both logs in base e) In this particular case, you can also solve the equation mentally - you don't even need a calculator! Just use the definition of a log: "To what power must I raise 5 to get 125?" The answer to this is, by definition, log5125. Similarly with log28.
How do you solve log x3?
You can't solve this since it isn't an equation.There is also an ambiguity (it's hard to write math on a typewriter keyboard) - are we talking about log(x3) or maybe logx(3)?Restate the question: Simplify log(x3)Answer: 3log(x)You could explain this by saying: log(x3) = log[(x)(x)(x)] = logx + logx + logx = 3logx. The general rule is log(xn) = nlogx.
How do you solve a log?
You calculate a log, you do not solve a log!
How do you solve 3 log of 8 equals x?
x = 3*log8 = log(83) = log(512) = 2.7093 (approx)
How do you solve log x plus log 8 equals 1?
log(x)+log(8)=1 log(8x)=1 8x=e x=e/8 You're welcome. e is the irrational number 2.7....... Often log refers to base 10 and ln refers to base e, so the answer could be x=10/8
I need to evaluate the following logarithm log base 8 of the cube root of 1by2.Plz solve?
The part we don't understand is: If you need to evaluate it, then why do we need to solve it ?Here's a suggestion on how to go about it:log8(0.51/3) = 1/3 log8(0.5)To find log8(0.5) : let's call it 'Q'8Q = 0.5Q log(8) = log(0.5)Q = log(0.5) / log(8)Now you can find 'Q', and then 1/3 of Q is the answer to your original question.
How do you solve log x - 2?
You cannot solve log x- 2 unless (i) log x - 2 is equal to some number or (ii) x is equal to some number.
What is 8(5 to the power of x) equal 23?
8 × 5^x = 23 → 5^x = 2.875 → x log 5 = log 2.875 → x = log 2.875 ÷ log 5 (You can use logs to any base as long as the same base is used for both of the logs.)
Which expressions are equivalent to log 2 - log 8?
-6
How can you solve 5 idices n equal 8 how can i find n when it appears as indice?
I understand this to mean 5n = 8 We try to convert equations like these into equations involving logarithms. Which is fairly easy. In the usual way that we might add constants to both sides of an equation of take square roots of both sides, let us just take logarithms of both sides of this one. n log 5 = log 8 (the logarithm of the power of a number is the product of the log of the number and the power) Then n = log 8 / log 5 ~= 1.29
What does x equals in 2 log x equals log 8?
2 log(x) = log(8)log(x2) = log(8)x2 = 8x = sqrt(8) = 2.82843 (rounded)Note that only the positive square root of 8 can serve as a solution to thegiven equation, since there's no such thing as the log of a negative number.
How do you solve for a power in a math problem?
You have to use logarithms (logs).Here are a few handy tools:If [ C = D ], then [ log(C) = log(D) ]log(AB) = log(A) + log(B)log(A/B) = log(A) - log(B)log(Np) = p times log(N)
Solve Log f plus log 0.1 equals 6?
log(f) + log(0.1) = 6 So log(f*0.1) = 6 so f*0.1 = 106 so f = 107
What is 8 log base 8 of 19?
The expression 8 log base 8 of 19 can be rewritten as log base 8 of 19 raised to the 8th power. This is because the logarithm function is the inverse of the exponentiation function. Therefore, 8 log base 8 of 19 simplifies to log base 8 of 19^8.
