x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
x = -3
x2-9x = x(x-9)
x: x2 - 81 = 0
x2 - 9x = -8 ∴ x2 - 9x + 8 = 0 ∴ (x - 1)(x - 8) = 0 You can then solve it as well: ∴ x ∈ {1, 8}
x - x2 - 9x + 14 = 0 ; whence, x2 + 8x = 14 , x2 + 8x + 16 = 30 , and x + 4 = ±√30 . Therefore, x = ±√30 - 4 .
9x2-9x = 0 x2-x = 0 x(x-1) = 0 x = 1 or x = 0
x2=9x-20 x2-9x+20=0 Factor: (x-4)(x-5)=0 x={4,5}
If you're looking to solve that equation for x, it can be done as follows: x2 + 9x = -7 x2 + 9x + (9/2)2 = (9/2)2 - 7 (x + 9/2)2 = 81/4 - 28/4 x + 9/2 = ±√(53/4) x = -9/2 ± √53/2
44 = 9x +8 36=9x 4=x
Re-arranging, x2 - 14x +49 = 0 Factorising, (x-2)(x-2) = 0, hence x=2.
2y - 9x = 14 2y = 14 + 9x y = (14 + 9x) / 2
9 x 27 equals 243
x = -3
Fsxjugfxbi
x2 = 6482 = 64x = 8