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To have a zero at 2, you need to include a factor (x - 2). To have a zero at 13 + i, you need a factor (x - (13 + i)). To have real coefficients, for each non-real factor you need to include its complex conjugate, so in this case, (x + 13 + i).Thus, you have the factors:

(x - 2)(x - (13 + i))(x + 13 + i)

You can multiply the factors together to get the polynomial into standard form. I suggest you start with the complex conjugates, that makes it easier.

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7y ago

x^3 - 28*x^2 + 222*x - 340 = 0

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Q: Write a polynomial degree with real coefficients whose zeros include 13 plus i and 2 Write the polynomial degree in standard form?
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