The question cannot be answered on two counts:
first of all, how "high" the tree is would mean how far off the ground the tree is, although the question probably meant how "tall" the tree is
more importantly, the question does not mention how tall the pole is, so it is not possible to determine how tall the tree is, even assuming that both the tree and the pole are at right angles to the ground
Answer
The ratio of the height of the pole (Hp) to the length o the shadow of the pole (Lsp) is the same as the ratio of the height of the tree (Ht) to the length of the shadow of the tree (Lst).
So
Hp/Lps = Ht/Lst
So inserting the known data:
Hp/11 = Ht/38
Then reorganizing:
Ht = 38/11 Hp = 3.45Hp
The tree is 3.45 times the height of the pole
The shadow:object ratio is 1:1 so the tree is 63 feet high.
If the tree is T ft high, then T/21 = 8/3 so that T = 21*8/3 = 56 feet.
27.3 feet
488 cm
The flag pole would be 20 feet. (You can see that the shadows are twice as long.) At a given time of the day, the length of a shadow cast by any object will have the same relationship to its actual height as all other objects. Here the ratio is 5/10 = x/40 and multiplying both sides by 40, 20 = x.
15 feet high
It works out as 12 feet and 4 inches in height
The shadow:object ratio is 1:1 so the tree is 63 feet high.
The height of the tree is in direct proportion to the pole and its shadow
(12 / 5) × 33 = 79.2 feet high Divide the pole shadow by the pole height: (12 / 5) = 2.4 feet Times the 2.4 by the tree shadow of 33 feet: 2.4 x 33 = 79.2
17.45 feet.
It is 90 feet in height
1. How high is a flagpole that casts a shadow of 45 ft at the same time a woman 5.5 ft tall casts a shadow 10 ft?
25 feet tall
Ratio of shadows = 3m:7.5m :: 1:2.5 So, the ratio of the heights (in the same order) is 1:2.5 ie Ht(Pole):Ht(Building) = 40m:Ht(Building) = 1:2.5 So Ht(Building) = 2.5*40m = 100 metres
50 feet
40 ft