this is the pythagorean theorem: x^2 + y^2 = c^2.
1) 12^2 + 16^ = c^2
2) 144 + 256 = c^2
3) 400 = c^2
4) Take the sq. root of both sides.
5) 20 = c
The diagonal of the garden is 20 meters.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
The diagonal is 14.142 feet.
43.26661530556787
The pieces would be arranged 4 by 4, That is 20 meters by 20 meters or 400 square meters.
68m
The diagonal of the garden is 20 meters.
The garden's diagonal is 10 meters.
Using Pythagoras' theorem the length of the diagonal is 15 units
20m
It is 10 metres.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
8.9
To find the diagonal of a rectangular face, you can use the Pythagorean theorem. For a rectangle with sides of 12 mm and 16 mm, the diagonal ( d ) is calculated as ( d = \sqrt{12^2 + 16^2} = \sqrt{144 + 256} = \sqrt{400} = 20 ) mm. Thus, the diagonal of the 12 mm-by-16 mm face is 20 mm long.
To find the area of a rectangular garden, you multiply its length by its width. For a garden that is 10 feet long and 3 feet wide, the area is calculated as 10 ft × 3 ft = 30 square feet. Thus, the area of the garden is 30 square feet.
long side= 5 short= 3 long = 7 short = 1 long= 6 short= 2
It is 60 feet.