this is the pythagorean theorem: x^2 + y^2 = c^2.
1) 12^2 + 16^ = c^2
2) 144 + 256 = c^2
3) 400 = c^2
4) Take the sq. root of both sides.
5) 20 = c
The diagonal of the garden is 20 meters.
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
The diagonal is 14.142 feet.
43.26661530556787
302+482=3204 squareroot(3204) Answer=56.60388679
68m
The garden's diagonal is 10 meters.
The diagonal of the garden is 20 meters.
Using Pythagoras' theorem the length of the diagonal is 15 units
20m
It is 10 metres.
8.9
The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles: 4X8 -> Diagonal is 8.944 ft 4X12 -> Diagonal is 12.649 ft 8X12 -> Diagonal is 14.422 ft
To find the diagonal of a rectangular face, you can use the Pythagorean theorem. For a rectangle with sides of 12 mm and 16 mm, the diagonal ( d ) is calculated as ( d = \sqrt{12^2 + 16^2} = \sqrt{144 + 256} = \sqrt{400} = 20 ) mm. Thus, the diagonal of the 12 mm-by-16 mm face is 20 mm long.
long side= 5 short= 3 long = 7 short = 1 long= 6 short= 2
It is 60 feet.
The diagonal is 10 metres.