The dimensions given appear to describe a rectangular box, with 3 separate pairs of rectangles:
4X8 -> Diagonal is 8.944 ft
4X12 -> Diagonal is 12.649 ft
8X12 -> Diagonal is 14.422 ft
43.26661530556787
302+482=3204 squareroot(3204) Answer=56.60388679
15 cm Solved through Pythagoras' theorem.
120 inches (by finding the hypotenuse of a right triangle).
Oh, dude, you're hitting me with the math questions now? Okay, okay, let me think. So, the diagonal of a rectangle can be found using the Pythagorean theorem, right? So, it's like the square root of (24 squared + 30 squared). That's like 36 feet. So, the diagonal of a 24 ft by 30 ft rectangle is 36 feet.
The diagonal is 221.2 inches long.
The diagonal is 15.652'
The diagonal is 14.21 cm
The diagonal would be 12.53 meters.
The diagonal is 100'
The diagonal is 48.877 feet.
The diagonal is 47.707'
The diagonal is 3.231 meters.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
26.4 inches for the diagonal.
15 cm for the diagonal.
2(21+12) = 66 feet