sqrt(24*36) = 29.4sqrt(24*36) = 29.4sqrt(24*36) = 29.4sqrt(24*36) = 29.4
sqrt (2 x 36 x 36) ie 50.94 inches
A rectangle with a perimeter of 36 units can have sides of any length as long as the lengths of the two differently-sized sides are equal to 18. For example, a rectangle with sides of 10 units and 8 units (don't forget to state what these units are, whether they are inches or centimetres or any other similar measurement), would have a perimeter of 36.
It could be the measurements of a woman, bust 36 inches, waist 24 inches, hips 36 inches.
The rectangle has a length of 12 cm and a width of 3 cm.
Use Pythagoras' therorem to find the diagonal of the rectangle which is 12 times the sq rt of 13
The diagonal is 45.61 feet.
36 inches
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
Perimeter = 25+36+25+36 = 122 units of measurement Use Pythagoras' theorem to find the other side of the rectangle
Using Pythagoras: 322+362 = 2320 and the square root of this is the length of the diagonal
a2 + b2 = c2. 62 + 82=c2. 36+64=c2. 100=c2. sqrt(100)=sqrt(c2). c=10. So the diagonal is 10 m. long.
By Pythagoras, (Diagonal)2 = 362 + 562 = 1296 + 3136 = 4432 sq ft So diagonal = +sqrt(4432) = 66.75 ft
The dimensions are 27cm by 36 cm, solved with the help of Pythagoras' theorem
Using Pythagoras its base works out as 36 and so 36*15 = 540 square units
60 feet Solved with the help of Pythagoras' theorem
To find the diagonal measurement of a square, you can use the Pythagorean theorem, which states that the square of the hypotenuse (the diagonal) is equal to the sum of the squares of the other two sides. In this case, both sides of the square are 36 feet long, so the diagonal can be calculated as √(36^2 + 36^2) = √(1296 + 1296) = √2592 ≈ 50.91 feet. Therefore, the diagonal measurement of a 36-foot by 36-foot square is approximately 50.91 feet.