0
Answer is 199.
The set of three-digit numbers starts at 000 and goes to 999. So we have to find each number with at least one "7" in this set.
In the first hundred (000 to 099), instances of one or more 7s occur 11 times, for:
007
017
027
037
047
057
067
070
077
087
097
This same sequence happens for the 100s, 200s, 300s, 400s, 500, 600s, 800, and 900s (notice I left out 700s). So far, this totals 11 times 9 = 99 instances.
Then we add the number in 700 through 799. Every one of these has at least one digit of 7, totaling 100 numbers.
So, in total, there are 11 * 9 + 100 = 199 instances.
000-099 has 11
100-199 has 11
200-299 has 11
300-399 has 11
400-499 has 11
500-599 has 11
600-699 has 11
700-799 has 100
800-899 has 11
900-999 has 11
-------------------
TOTAL = 199
Add your answer:
Earn +20 pts
Whole no between 1 and 100 use the digit 6 at least once?
use the digit 1234to make two different numbers
Which digit in 4.628 has the least value?
The number 8 in that question is the number with the least amount of value (0.008).
Put these in order from least to greatest 8689969395827786959886?
If those are two-digit numbers, the answer is 77, 82, 86, 86, 86, 89, 93, 95, 95, 96, 98
Which digit in 305.8 has the least value?
.8
What digit has the least value in 16589?
It is 9
What is the least possible sum of two 4-digit numbers?
what is the least possible sum of two 4-digit numbers?what is the least possible sum of two 4-digit numbers?
What is the least six digit numbers?
100,000
What are the greatest and least 6 digit numbers in which the digit in the ten thousands place is twice the digit in the tens place?
Greatest: 989949 Least: 100000
What is the least 4-digit prime numbers?
It is: 1013
What is the least number in single digit numbers?
0
What is the least sum you can get when adding two four-digit numbers?
2000.The smallest four-digit number there can be is 1000. So, add 1000 and 1000 to get 2000, then least sum you can get when adding two four-digit numbers.
How many 3 digit numbers contain the digit 2 at least once?
252
Why the product of two 2-digit numbers must be at least 100?
-98
What is the least sum you can get wheyou add 2-digit numbers?
21
What digit is the least frequent between the numbers 1 and 1000?
Zero
How many seven digit numbers contain the number seven at least once?
To find the total number of seven-digit numbers that contain the number seven at least once, we can use the principle of complementary counting. There are a total of 9,999,999 seven-digit numbers in total. To find the number of seven-digit numbers that do not contain the number seven, we can count the number of choices for each digit (excluding seven), which is 9 choices for each digit. Therefore, there are 9^7 seven-digit numbers that do not contain the number seven. Subtracting this from the total number of seven-digit numbers gives us the number of seven-digit numbers that contain the number seven at least once.
Note that both 100 and 999 satisfy this condition How many numbers from 100 to 999 inclusive have a hundreds digit that is at least the tens digit and a tens digit that is at least the ones digit?
how does 100 meet the specification? 1 is in the hundreds digit and 0 is in the tens digit. 1 is not at least 0. this is a confusing question?!
