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There are 7 digits from 0-6

To determine if a number is divisible by 4, we only need look at the last 2 digits. Possibilities are:

[135][26] => 12, 16, 32, 36, 52, 56

and

[0246][04] => 04, 20, 24, 40, 60, 64 (ignoring 00 and 44)

There are 8 combinations without a 0, and 4 with a 0.

Of the 8 combinations without a 0, We can only pick 4 of the remaining digits for the ten thousand digit. This leaves us with 4 digits for the thousands digit, 3 for the hundreds digit

Of the 4 combinations with a 0, similarly we have 5 X 4 X 3 possibilities for the rest of the digits.

8 * 4 * 4* 3 + 4 * 5 * 4 * 3

= 32 * 12 + 20 * 12

= 52 * 12

= 624

There are 624 possible numbers.

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Q: How many 5 digit numbers that are divisible by 4 can be formed using the digits from 0 to 6 if no digit is to occur more than once in each number?
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Related questions

What are some numbers that are divisible by four?

numbers that are divisible by 4 is either: 4n or numbers in which the number formed by last two digits are divisible by 4


How do you know if a number is divisible by four?

Whole numbers are divisible by 4 if the number formed by the last two individual digits is evenly divisible by 4. For example, the number formed by the last two digits of the number 2628 is 28, which is evenly divisible by 4 so the number 2628 is evenly divisible by 4.


How do you know when a number is divisible by 8?

Numbers are divisible by 8 if the number formed by the last three individual digits is evenly divisible by 8. For example, the last three digits of the number 3624 is 624, which is evenly divisible by 8 so 3624 is evenly divisible by 8.


How many 5 digit number can be formed using the digits 02345when repetition is allowed such that the number formed is divisible by 2 or 5 or both?

There are 2000 such numbers.


How many 5 digits can be formed using the digits 0 2 3 4 5 when repetition is allowed that the number formed is divisible by 2 and 5 or both?

There are 2000 such numbers.


A number is divisible by 8 the number formed by its last?

If the last three digits of a number are divisible by 8, the whole number is divisible by 8.


How do you know what is divisible by 8?

If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!


How do you explain that even without listing all the factors of a number it is easy to tell that they are composite numbers?

To know if a number is composite without listing its factors, you can use these rules:All numbers that end with 2, 4, 6, 8, and 0 (even numbers) are divisible by 2.If the sum of the digits in a number is divisible by 3, the number is divisible by 3.If the last two digits are divisible by 4, the number is divisible by 4.All numbers that have 5 in the one's place are divisible by 5.If a number is divisible by 2 AND is divisible by 3, it is divisible by 6.If the last 3 digits of a number are divisible by 8, the number is divisible by 8.If the sum of the digits of number is divisible by 9, the number is divisible by 9.If a number ends wuth 0, the number is divisible by 10.


A number is divisible by 8 if?

If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.


Is a number always divisible by 4 if the sum of the digits is 8?

No. 26 for instance the sum of the digits is 8 but not divisible by 4. 32 the sum of the digits is 5 but divisible by 4 The rules for some other numbers are 2 all even numbers are divisible by 2 3 The sum of the digits is divisible by 3 4 The last 2 numbers are divisible by 4 5 The number ends in a 0 or 5 6 The sum of the digits is divisible by 3 and is even 7 no easy method 8 The last 3 numbers are divisible by 8 9 The sum of the digits is divisible by 9


What are the divisibility rules for 1 2 3 4 5 6 9 and 10?

All whole numbers are divisible by 1. Numbers are divisible by 2 if they end in 2, 4, 6, 8 or 0. Numbers are divisible by 3 if the sum of their digits is divisible by 3. Numbers are divisible by 4 if the last two digits of the number are divisible by 4. Numbers are divisible by 5 if the last digit of the number is either 5 or 0. Numbers are divisible by 6 if they are divisible by 2 and 3. Numbers are divisible by 9 if the sum of their digits is equal to 9 or a multiple of 9. Numbers are divisible by 10 if the last digit of the number is 0.


Can you make a prime number from the numbers 1 0 8?

A prime number is only divisible by 1 and itself. If all three digits have to be used then any number formed from them is divisible by 9 as the sum of the digits = 9. Thus no prime number can be formed. If only two of the three digits are used then it cannot end in 0 or 8 as it would be divisible by 2. This only leaves 81 where the digits again total 9 and thus is divisible by 9. None of the single digits 0,1,8 are prime. 8 is an even number. 1 is classed as unity, 0 is zero.