To calculate the number of combinations of 4 numbers from 8 numbers, you would use the combination formula, which is nCr = n! / (r!(n-r)!). In this case, n = 8 and r = 4. Plugging these values into the formula, you get 8C4 = 8! / (4!(8-4)!) = 70. Therefore, there are 70 possible combinations of 4 numbers that can be chosen from a set of 8 numbers.
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Well, honey, if you're looking to pick 4 numbers out of a pool of 8, you're looking at a total of 70 possible combinations. It's like trying to pick your favorite Golden Girl - there's only so many options to choose from! Just remember, math doesn't have to be as complicated as trying to keep up with Blanche's love life.
Oh, dude, math time! So, to find the number of combinations of 4 numbers from 8 numbers, you can use the formula for combinations, which is 8 choose 4. This gives you 70 possible combinations. So, like, you have 70 ways to pick 4 numbers from 8. Math is wild, man.
Two . . . . . 38 and 83.
(9 x 8 x 7 x 6 x 5 x 4)/(6 x 5 x 4 x 3 x 2) = 84 combinations.
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
To calculate the number of combinations for the numbers 1248, we need to consider all possible arrangements of the four digits. Since all the digits are unique, there are 4 factorial (4!) ways to arrange them. This equals 4 x 3 x 2 x 1 = 24 combinations.
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations