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Your a bum 4 lising 2 me
2 4 6 8
2 4 8 6
2 6 4 8
2 6 8 4
2 8 4 6
2 8 6 4
4 2 6 8
4 2 8 6
4 6 2 8
4 6 8 2
4 8 2 6
4 8 6 2
6 2 4 8
6 2 8 4
6 4 2 8
6 4 8 2
6 8 2 4
6 8 4 2
8 2 4 6
8 2 6 4
8 4 2 6
8 4 6 2
8 6 2 4
8 6 4 2
That's all 24 possible combinations.
To find the combinations for the numbers 2, 4, 6, and 8, you can use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, you would calculate the combinations for choosing 2, 3, or 4 numbers from the set of 4. So, the combinations would be:
- Choosing 2 numbers from 4: 4C2 = 6 combinations
- Choosing 3 numbers from 4: 4C3 = 4 combinations
- Choosing all 4 numbers: 4C4 = 1 combination.
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What are the combinations for 2 6 8?
To calculate the combinations for the numbers 2, 6, and 8, we need to use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, we have 3 numbers (n=3) and we want to choose 2 of them (r=2). So, the combinations would be 3C2 = 3! / 2!(3-2)! = 3. Therefore, the combinations for 2, 6, and 8 are (2, 6), (2, 8), and (6, 8).
How many combinations of 2 digits are possible using the digits 4 7 0 8 and 2?
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many combinations are there if you have 8 numbers and there are 6 number combinations Just like in the maga millions lottery?
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.
What are the 4 digit combinations of the numbers 0 through 9?
There are 10!/(4!(10-4)!) = 210 such combinations assuming no repeats are allowed: {0, 1, 2, 3}, {0, 1, 2, 4}, {0, 1, 2, 5}, {0, 1, 2, 6}, {0, 1, 2, 7}, {0, 1, 2, 8}, {0, 1, 2, 9}, {0, 1, 3, 4}, {0, 1, 3, 5}, {0, 1, 3, 6}, {0, 1, 3, 7}, {0, 1, 3, 8}, {0, 1, 3, 9}, {0, 1, 4, 5}, {0, 1, 4, 6}, {0, 1, 4, 7}, {0, 1, 4, 8}, {0, 1, 4, 9}, {0, 1, 5, 6}, {0, 1, 5, 7}, {0, 1, 5, 8}, {0, 1, 5, 9}, {0, 1, 6, 7}, {0, 1, 6, 8}, {0, 1, 6, 9}, {0, 1, 7, 8}, {0, 1, 7, 9}, {0, 1, 8, 9}, {0, 2, 3, 4}, {0, 2, 3, 5}, {0, 2, 3, 6}, {0, 2, 3, 7}, {0, 2, 3, 8}, {0, 2, 3, 9}, {0, 2, 4, 5}, {0, 2, 4, 6}, {0, 2, 4, 7}, {0, 2, 4, 8}, {0, 2, 4, 9}, {0, 2, 5, 6}, {0, 2, 5, 7}, {0, 2, 5, 8}, {0, 2, 5, 9}, {0, 2, 6, 7}, {0, 2, 6, 8}, {0, 2, 6, 9}, {0, 2, 7, 8}, {0, 2, 7, 9}, {0, 2, 8, 9}, {0, 3, 4, 5}, {0, 3, 4, 6}, {0, 3, 4, 7}, {0, 3, 4, 8}, {0, 3, 4, 9}, {0, 3, 5, 6}, {0, 3, 5, 7}, {0, 3, 5, 8}, {0, 3, 5, 9}, {0, 3, 6, 7}, {0, 3, 6, 8}, {0, 3, 6, 9}, {0, 3, 7, 8}, {0, 3, 7, 9}, {0, 3, 8, 9}, {0, 4, 5, 6}, {0, 4, 5, 7}, {0, 4, 5, 8}, {0, 4, 5, 9}, {0, 4, 6, 7}, {0, 4, 6, 8}, {0, 4, 6, 9}, {0, 4, 7, 8}, {0, 4, 7, 9}, {0, 4, 8, 9}, {0, 5, 6, 7}, {0, 5, 6, 8}, {0, 5, 6, 9}, {0, 5, 7, 8}, {0, 5, 7, 9}, {0, 5, 8, 9}, {0, 6, 7, 8}, {0, 6, 7, 9}, {0, 6, 8, 9}, {0, 7, 8, 9}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 3, 6}, {1, 2, 3, 7}, {1, 2, 3, 8}, {1, 2, 3, 9}, {1, 2, 4, 5}, {1, 2, 4, 6}, {1, 2, 4, 7}, {1, 2, 4, 8}, {1, 2, 4, 9}, {1, 2, 5, 6}, {1, 2, 5, 7}, {1, 2, 5, 8}, {1, 2, 5, 9}, {1,2, 6, 7}, {1, 2, 6, 8}, {1, 2, 6, 9}, {1, 2, 7, 8}, {1, 2, 7, 9}, {1, 2, 8, 9}, {1, 3, 4, 5}, {1, 3, 4, 6}, {1, 3, 4, 7}, {1, 3, 4, 8}, {1, 3, 4, 9}, {1, 3, 5, 6}, {1, 3, 5, 7}, {1, 3, 5, 8}, {1, 3, 5, 9}, {1, 3, 6, 7}, {1, 3, 6, 8}, {1, 3, 6, 9}, {1, 3, 7, 8}, {1, 3, 7, 9}, {1, 3, 8, 9}, {1, 4, 5, 6}, {1, 4, 5, 7}, {1, 4, 5, 8}, {1, 4, 5, 9}, {1, 4, 6, 7}, {1, 4, 6, 8}, {1, 4, 6, 9}, {1, 4, 7, 8}, {1, 4, 7, 9}, {1, 4, 8, 9}, {1, 5, 6, 7}, {1, 5, 6, 8}, {1, 5, 6, 9}, {1, 5, 7, 8}, {1, 5, 7, 9}, {1, 5, 8, 9}, {1, 6, 7, 8}, {1, 6, 7, 9}, {1, 6, 8, 9}, {1, 7, 8, 9}, {2, 3, 4, 5}, {2, 3, 4, 6}, {2, 3, 4, 7}, {2, 3, 4, 8}, {2, 3, 4, 9}, {2, 3, 5, 6}, {2, 3, 5, 7}, {2, 3, 5, 8}, {2, 3, 5, 9}, {2, 3, 6, 7}, {2, 3, 6, 8}, {2, 3, 6, 9}, {2, 3, 7, 8}, {2, 3, 7, 9}, {2, 3, 8, 9}, {2, 4, 5, 6}, {2, 4, 5, 7}, {2, 4, 5, 8}, {2, 4, 5, 9}, {2, 4, 6, 7}, {2, 4, 6, 8}, {2, 4, 6, 9}, {2, 4, 7, 8}, {2, 4, 7, 9}, {2, 4, 8, 9}, {2, 5, 6, 7}, {2, 5, 6, 8}, {2, 5, 6, 9}, {2, 5, 7, 8}, {2, 5, 7, 9}, {2, 5, 8, 9}, {2, 6, 7, 8}, {2, 6, 7, 9}, {2, 6, 8, 9}, {2, 7, 8, 9}, {3, 4, 5, 6}, {3, 4, 5, 7}, {3, 4, 5, 8}, {3, 4, 5, 9}, {3, 4, 6, 7}, {3, 4, 6, 8}, {3, 4, 6, 9}, {3, 4, 7, 8}, {3, 4, 7, 9}, {3, 4, 8, 9}, {3, 5, 6, 7}, {3, 5, 6, 8}, {3, 5, 6, 9}, {3, 5, 7, 8}, {3, 5, 7, 9}, {3, 5, 8, 9}, {3, 6, 7, 8}, {3, 6, 7, 9}, {3, 6, 8, 9}, {3, 7, 8, 9}, {4, 5, 6, 7}, {4, 5, 6, 8}, {4, 5, 6, 9}, {4, 5, 7, 8}, {4, 5, 7, 9}, {4, 5, 8, 9}, {4, 6, 7, 8}, {4, 6, 7, 9}, {4, 6, 8, 9}, {4, 7, 8, 9}, {5, 6, 7, 8}, {5, 6, 7, 9}, {5, 6, 8, 9}, {5, 7, 8, 9}, {6, 7, 8, 9} If repeats are allowed, the number increases to 715 combinations - I'll leave it as an exercise for the reader to list the extra 505 combinations.
What are the possible combinations of numbers 0 through 9 if any numbers cannot be repeated?
There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.
What are the combinations for 2 6 8?
To calculate the combinations for the numbers 2, 6, and 8, we need to use the formula for combinations, which is nCr = n! / r!(n-r)!. In this case, we have 3 numbers (n=3) and we want to choose 2 of them (r=2). So, the combinations would be 3C2 = 3! / 2!(3-2)! = 3. Therefore, the combinations for 2, 6, and 8 are (2, 6), (2, 8), and (6, 8).
How many combinations of 6 in 8?
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
How many dice combinations total less than 8 2 6sided dice?
With 2 6-sided dices there are 6x6=36 combinations (6 for the first dice, 6 for the second dice) Let put the question this other way: how many combinations with a total more than 8, namely 9, 10, 11 or 12 ? 9: 4 combinations: 4-5 or 5-4 or 6-3 or 3-6 10: 3 combination: 5-5 or 6-4 or 4-6 11: 2 combinations: 6-5 or 5-6 12: 1 combination: 6-6 So there are 10 combinations for "more than 9" thus there are 36-10=26 combinations for "less or equal to 8".
How many combinations of 6 numbers are there in 10 numbers?
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
How many combinations can you make only using 4 7 8?
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
How can 80 be split into groups of 6 8 10?
here are all the possible combinations 6(12)+8 6(10)+10(2) 6(9)+8(2)+10 6(8)+8(4) 6(7)+8+10(3) 6(6)+8(3)+10(2) 6(5)+8(5)+10 6(5)+10(5) 6(4)+8(2)+10(4) 6(4)+8(7) 6(3)+8(4)+10(3) 6(2)+8+10(6) 6(2)+8(6)+10(2) 6+8(3)+10(5) 6+8(8)+10 8(10) 8(5)+10(4) 10(8)
How many combinations of 2 are there in 8?
4
How many numbers can you make with 3 7 8 9?
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
How many combinations of 2 digits are possible using the digits 4 7 0 8 and 2?
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
How many combinations can you make with the numbers 2 3 6 7 and 8?
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
How many combinations are there if you have 8 numbers and there are 6 number combinations Just like in the maga millions lottery?
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.
