There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.
Nine options, no repeats, three slots.The equation for this is as follows:9!/(3!*(9-3)!)9*8*7*6*5*4*3*2*1 / (3*2*1)*(6*5*4*3*2*1)= 9*8*7 / 3*2*1= 504 / 6= 252 / 3= 8484 combinations.
There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}There are 8 possible combinations:{},{2},{6},{8},{2,6},{2,8},{6,8} and{2,6,8}
There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.There are 10 combinations of 1 number,10*9/(2*1) = 45 combinations of 2 numbers,10*9*8/(3*2*1) = 120 combinations of 3 numbers,10*9*8*7/(4*3*2*1) = 210 combinations of 4 numbers,10*9*8*7*6/(5*4*3*2*1) = 252 combinations of 5 numbers,210 combinations of 6 numbers,120 combinations of 7 numbers,45 combinations of 8 numbers,10 combinations of 9 numbers, and1 combination of 10 numbers.All in all, 210 - 1 = 1023 combinations. I have neither the time nor inclination to list them all.
(8 x 7 x 6 x 5 x 4 x 3)/(6 x 5 x 4 x 3 x 2) = 28 combinations
With 2 6-sided dices there are 6x6=36 combinations (6 for the first dice, 6 for the second dice) Let put the question this other way: how many combinations with a total more than 8, namely 9, 10, 11 or 12 ? 9: 4 combinations: 4-5 or 5-4 or 6-3 or 3-6 10: 3 combination: 5-5 or 6-4 or 4-6 11: 2 combinations: 6-5 or 5-6 12: 1 combination: 6-6 So there are 10 combinations for "more than 9" thus there are 36-10=26 combinations for "less or equal to 8".
The answer is 10!/[6!*(10-6)!] where n! represents 1*2*3*...*n Number of combinations = 10*9*8*7*6*5*4*3*2*1/(6*5*4*3*2*1*4*3*2*1) = 10*9*8*7/(4*3*2*1) = 210
6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations
here are all the possible combinations 6(12)+8 6(10)+10(2) 6(9)+8(2)+10 6(8)+8(4) 6(7)+8+10(3) 6(6)+8(3)+10(2) 6(5)+8(5)+10 6(5)+10(5) 6(4)+8(2)+10(4) 6(4)+8(7) 6(3)+8(4)+10(3) 6(2)+8+10(6) 6(2)+8(6)+10(2) 6+8(3)+10(5) 6+8(8)+10 8(10) 8(5)+10(4) 10(8)
4
14 * * * * * Wrong! There are 15. 4 combinations of 1 number, 6 combinations of 2 number, 4 combinations of 3 numbers, and 1 combination of 4 numbers.
10 combinations- 4&7, 4&0, 4&8, 4&2, 7&0, 7&8, 7&2, 0&8, 0&2, and 8&2
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
From 8 numbers there are 28 possible 6 number combinations. As you are selecting 6 numbers from 8 and the order of selection doesn't matter: First, there are 8 x 7 x 6 x 5 x 4 x 3 ways that 6 numbers can be selected in order. However, as the order doesn't matter, each 6 number combinations will be selected in 6 x 5 x 4 x 3 x 2 x 1 ways. Thus there are (8 x 7 x 6 x 5 x 4 x 3) ÷ (6 x 5 x 4 x 3 x 2 x 1) = 28 different combinations.