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How many ways can seven books be arranged on a shelf if one of the books is an algebra text and it must be in the center?
it depends on the shelf of course
How many ways can 10 books be arranged if 4 math books are keeped toghter?
While massaging the question into some form that can be answered,I'm assuming:-- exactly 4 of the 10 books are math books-- the other 6 are not math books-- you're asking how many different ways all 10 can be arrangedon the shelf while keeping the math books all together.If that's your question, then the answer is as follows. If that's not your question,then the following is the answer to my question but it won't help you at all :The 10 books are really only 7 units to be arranged ... 6 random books, andone unit comprised of math books that might as well be glued together becausethey can't separated. So the shelf arrangement involves lining up 7 things.The first can be any one of the seven. For each of those . . .The second one can be any one of the remaining six. For each of those . . .The third can be any one of the remaining five. For each of those . . ...etc.Total number of possible arrangements is (7 x 6 x 5 x 4 x 3 x 2) = 5,040 ways.
In how many different ways can five runners be arranged?
5! = 120
How many ways can 5 CDs be arranged on a shelf?
5! = 5 x 4 x 3 x 2 x 1 = 120 ways.
How many ways can you arrange 4 books on a shelf?
The answer to this one is 24. You can do this mathematically by 4*3*2*1.
