8 ! = 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1 = 40320
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
240. 120 ways with the books stacked verticly, and 120 ways with the books stacked horizontaly, or one on top of the other.
One row of 5 different brands with each type being represented can be arranged in 5x4x3x2x1= 120 ways
3 from 6 = 6 x 5 x 4 x 3 x 2)/3 x 2 x 3 x 2 = 20 different sets of 3 which can then be arranged 3 x 2 different ways so the answer is 120. See if you can find them all!
The number of ways that 15 books can be arranged on a shelf is the same as the number of permutations of 15 things taken 15 at a time. This is 15 factorial, or 15!, and is 1,307,674,368,000.
There are 2*5! = 240 ways.
it depends on the shelf of course
Slowly and methodically, I arranged the books on the shelf.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
The number of permutations of five things taken five at a time is five factorial, or 120.
5040
5
The answer depends on how many books on each subject there are.
6! = 1 x 2 x 3 x 4 x 5 x 6.
You can wind up with 10 different pairs of books in your hand, which you can choose from a shelf of 5 books in 20 different ways.
Using the binomial coefficient and the 'choose' function, 10 books can be arranged 10! = 10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 3628800 different ways.