Counting just positive numbers, we have all numbers from 100000 to 999999, the difference is 899,999, but because we count both the starting and ending number, we have to add 1 to this, which makes it 900,000 numbers. Of course if you want to include also negative numbers that makes it 1,800,000. And because we want only EVEN numbers these totals would be divided by 2, so there are 450,000 positive, even, 6 digit numbers and 450,000 negative, even, 6 digit numbers. Total is 900,000. This is considering whole numbers only. If we include ALL numbers than we would also have to count the six digit numbers between 1 and -1... such as .000002 through .999998 thereby doubling again the total to 1.8 million.
The pages of a book are numbered from 1 to 128. How many page numbers contain the digit 6?
The final digit must be a 2 to form an even number. The first digit may be any of three remaining digits (1, 3, 5) while the second digit may be any of the two remaining digits. All together, that makes 3*2 = 6 distinct even numbers.
If you can repeat a digit, there are 27. If you can't repeat a digit, there are only 6.
If the same digit can be used more than once: 6 x 6 x 6 = 216 of them. If each digit can be used only once: 6 x 5 x 4 = 120 of them.
Any 3 out of 4 = 4. Each set can be arranged 6 ways so 24 different numbers.
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .
There are 151 3-digit numbers that are divisible by 6.
6 x 6 x 6 x 3 = 648 6 because the first digit can be any of the numbers 6 again, because the second digit can be any of the numbers 6, again, because the third digit can be any of the numbers 3, because the fourth/last digit can only be 2, 4, or 6
To form a 6-digit even number, the leftmost digit can be any digit from 1 to 9 (9 options), while the last digit must be even (0, 2, 4, 6, or 8, giving 5 options). The remaining four digits can be any digit from 0 to 9 (10 options each). Therefore, the total number of 6-digit even numbers is calculated as: (9 \times 10^4 \times 5 = 450,000).
24 of them. So we have a 2 or 6 in the unit position, therefore (2)(4)(3) = 24 even three-digit numbers, can be formed.
6*6*3 = 108 numbers.
18
There are 16 4-digit numbers that can be made up from 9 and 6.
The ones digit in even numbers can be any of the following: 0, 2, 4, 6, or 8. This is because even numbers are divisible by 2, meaning they can be expressed as 2 multiplied by another integer. The ones digit is the digit in the ones place of a number, which can range from 0 to 9.
The two-digit numbers with both digits even are formed using the even digits 0, 2, 4, 6, and 8. However, since the first digit (the tens place) cannot be 0, the possible choices for the first digit are 2, 4, 6, and 8 (4 options). The second digit (the units place) can be 0, 2, 4, 6, or 8 (5 options). Therefore, the total number of two-digit numbers with both digits even is (4 \times 5 = 20).
if the repetition is allowed the there is 6*6*6 possible ways = 216
900,000.