900,000.
I suggest you calculate (1) how many numbers are in total, and (2) how many numbers in that range do NOT have 6 as a digit. Then you can subtract the result of (1) minus the result of (2).
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .
To form 4-digit numbers using the digits 4, 7, 6, and 0, we must ensure that the first digit is not 0. The valid choices for the first digit are 4, 7, or 6, giving us 3 options. After choosing the first digit, we can arrange the remaining 3 digits in any order, resulting in (3! = 6) arrangements for each choice of the first digit. Thus, the total number of 4-digit numbers is (3 \times 6 = 18).
6
To form a 3-digit number using the digits 5, 6, and 8, we can use each digit in any position. Since we have three digits and they can be repeated, we have 3 choices for the first digit, 3 choices for the second digit, and 3 choices for the third digit. Therefore, the total number of 3-digit numbers is (3 \times 3 \times 3 = 27).
total 6- 18,19,81,89,91,98
There are 151 3-digit numbers that are divisible by 6.
The answer will depend on how many digits there are in each of the 30 numbers. If the 30 numbers are all 6-digit numbers then the answer is NONE! If the 30 numbers are the first 30 counting numbers then there are 126 combinations of five 1-digit numbers, 1764 combinations of three 1-digit numbers and one 2-digit number, and 1710 combinations of one 1-digit number and two 2-digit numbers. That makes a total of 3600 5-digit combinations.
I suggest you calculate (1) how many numbers are in total, and (2) how many numbers in that range do NOT have 6 as a digit. Then you can subtract the result of (1) minus the result of (2).
There are 16 4-digit numbers that can be made up from 9 and 6.
Total number of 2-digit numbers = (99 - 9) = 90 of themEvery number that isn't a perfect square has an even number of factors.2-digit numbers that are perfect squares: 16, 25, 36, 49, 64, and 81 = 6 of themRemaining 2-digit numbers = (99 - 6) = 93 .
if the repetition is allowed the there is 6*6*6 possible ways = 216
6
To form 4-digit numbers using the digits 4, 7, 6, and 0, we must ensure that the first digit is not 0. The valid choices for the first digit are 4, 7, or 6, giving us 3 options. After choosing the first digit, we can arrange the remaining 3 digits in any order, resulting in (3! = 6) arrangements for each choice of the first digit. Thus, the total number of 4-digit numbers is (3 \times 6 = 18).
15 of them are.
6! = 720
There are 60480 numbers.