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How many 3 digit positive integers have 5 as the product of their digits?
Three of them.
How many three-digit positive integers have digits whose product is 24?
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
What is the sum of all the positive two-digit integers where one of the digits is three times the other?
31 + 62 + 93 + 13 + 26 + 39 = 264
Value of the digit 5.68?
5.68 is not a digit, it is three digits.
What is quotient for three-digits divided by one digit?
2 or 3 digits.
How many 3 digit positive integers have 5 as the product of their digits?
Three of them.
What is the largest three-digit number with exactly two factors that are positive integers?
997
How many positive integers have exactly three digits?
Every number from 100 to 999 inclusive !
How many three-digit positive integers have digits whose product is 24?
To find the number of three-digit positive integers with digits whose product is 24, we can break down 24 into its prime factors: 2 x 2 x 2 x 3. The possible combinations for the three digits are (2, 2, 6), (2, 3, 4), and (2, 4, 3). These can be arranged in 3! ways each, giving a total of 3 x 3! = 18 three-digit positive integers.
How many positive integers with exactly three decimal digit positive integers between 100 and 999 inclusive divisible by 7?
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.
How many positive integers are there less than 900 such that digits are odd?
To find the number of positive integers less than 900 with all odd digits, we consider the digits available: 1, 3, 5, 7, and 9. For a three-digit number, the first digit (hundreds place) can only be 1, 3, 5, 7, or 9 (5 options), while the tens and units places can also be any of the 5 odd digits (5 options each). Thus, there are (5 \times 5 \times 5 = 125) three-digit numbers. For two-digit numbers, the first digit can again be any of the 5 odd digits, and the second digit can also be any of the 5 odd digits, giving (5 \times 5 = 25). Finally, for one-digit numbers, there are 5 options (1, 3, 5, 7, 9). Adding these together gives (125 + 25 + 5 = 155) positive integers less than 900 with all odd digits.
How many positive three-digit integers are divisible by neither 2 or 3?
the range of three-digit integers is from 100 to 999. Therefore, there are 300 positive three-digit integers that are divisible by neither 2 nor 3.1 day ago
What is the sum of all the positive two-digit integers where one of the digits is three times the other?
31 + 62 + 93 + 13 + 26 + 39 = 264
Value of the digit 5.68?
5.68 is not a digit, it is three digits.
What is the smallest three-digit number with all the digits different?
102 is the smallest three digit number with different digits.
What is the greatest six digit odd number using three different digits only?
In this type of question, you need to fill out the largest digit you can, one at a time, from left to right. The largest digit you can use for the leftmost position, is 9, the largest digit for the next position is 9, etc.; in summary, the final result is:999999 (if you want AT MOST three different digits), or 999987 (if you want EXACTLY three different digits).
How many three digit numbers have the property that the middle digit is the arithmetic mean of the other two digits?
To find the three-digit numbers where the middle digit is the arithmetic mean of the other two digits, we denote a three-digit number as ( abc ), where ( a, b, c ) are its digits. The condition means ( b = \frac{a + c}{2} ), which implies ( a + c ) must be even. For ( a ) (1-9) and ( c ) (0-9), ( b ) must be an integer and a digit (0-9). The pairs ( (a, c) ) that yield valid integers for ( b ) can be counted, leading to 45 valid combinations for three-digit numbers. Thus, there are 45 such three-digit numbers where the middle digit is the arithmetic mean of the other two.
