There are 24 combinations using each digit once per combination: 1234 1243 1324 1342 1423 1432 2134 2143 2314 2341 2413 2431 3124 3142 3214 3241 3412 3421 4123 4132 4213 4231 4312 and 4321.
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To calculate the number of 4-digit combinations using the numbers 1-4, we need to use the fundamental counting principle. Since there are 4 options for each digit in the combination, we multiply the number of options for each digit together: 4 options for the 1st digit * 4 options for the 2nd digit * 4 options for the 3rd digit * 4 options for the 4th digit = 4^4 = 256 possible combinations.
Well, isn't that just a happy little question! When you have 4 digits to choose from (1, 2, 3, 4) for each of the 4 positions, you can create a total of 4 x 4 x 4 x 4 = 256 unique combinations. Just imagine all the beautiful possibilities you can create with those numbers!
Oh, dude, there are 256 possible 4-digit combinations using the numbers 1-4. You just raise the number of options (4) to the power of the number of digits (4), so it's like 4x4x4x4. It's not rocket science, just basic math, man.
I am 11 and I tried this for fun.
I found 287 combinations.
Now I am working on 9 digit with numbers 1 - 9.
Wish me luck...
There are 5,040 combinations.
To calculate the number of 4-digit combinations you can get from the numbers 1, 2, 2, and 6, we need to consider that the number 2 is repeated. Therefore, the total number of combinations is calculated using the formula for permutations of a multiset, which is 4! / (2!1!1!) = 12. So, there are 12 unique 4-digit combinations that can be formed from the numbers 1, 2, 2, and 6.
I can't
First digit can be one of four, second can be one of the remaining three etc so 4 x 3 x 2 x 1 = 24 combinations. This is known as factorial 4 (or 4 factorial) and is symbolised as "4!".
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