Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
It can have 1, 2 or 3 unique roots.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
5, Using complex numbers you will always get 5 roots.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
A third degree polynomial could have one or three real roots.
4, the same as the degree of the polynomial.
No. A polynomial can have as many degrees as you like.
It can have 1, 2 or 3 unique roots.
Four.Four.Four.Four.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
5, Using complex numbers you will always get 5 roots.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
Well, honey, a polynomial equation can have multiple solutions, depending on the degree of the polynomial. A polynomial of degree "n" can have at most "n" solutions, including complex solutions. So buckle up and solve those equations, darlin'!
The answer is two. Despite its name seems to suggest something to do with four, in a quadratic equation the unknown appears at most to the power of two and so is said to be of second degree. The theorem than pertains here is that the number of roots an equation has is equal to its degrees. However, some of the roots can be repeated - an nth degree equation need not have n different roots. Also the roots do not have to be real. However complex roots ( no real) come in pairs so an equation of odd degree must have at least one real root. A quadratic possibly has no real roots.