Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
It can have 1, 2 or 3 unique roots.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
5, Using complex numbers you will always get 5 roots.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
A third-degree equation has, at most, three roots. A fourth-degree polynomial has, at most, four roots. APEX 2021
A third degree polynomial could have one or three real roots.
4, the same as the degree of the polynomial.
No. A polynomial can have as many degrees as you like.
It can have 1, 2 or 3 unique roots.
Four.Four.Four.Four.
Sort of... but not entirely. Assuming the polynomial's coefficients are real, the polynomial either has as many real roots as its degree, or an even number less. Thus, a polynomial of degree 4 can have 4, 2, or 0 real roots; while a polynomial of degree 5 has either 5, 3, or 1 real roots. So, polynomial of odd degree (with real coefficients) will always have at least one real root. For a polynomial of even degree, this is not guaranteed. (In case you are interested about the reason for the rule stated above: this is related to the fact that any complex roots in such a polynomial occur in conjugate pairs; for example: if 5 + 2i is a root, then 5 - 2i is also a root.)
5, Using complex numbers you will always get 5 roots.
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
Upto 4. If the coefficients are all real, then it can have only 0, 2 or 4 real roots.
The expression (6x^{16} - 22 + 6x) is a polynomial in (x) of degree 16. A polynomial of degree (n) can have up to (n) real solutions. Therefore, this polynomial can have up to 16 solutions, depending on the specific values of the coefficients and the nature of the roots.
Well, honey, a polynomial equation can have multiple solutions, depending on the degree of the polynomial. A polynomial of degree "n" can have at most "n" solutions, including complex solutions. So buckle up and solve those equations, darlin'!