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Evaluate the expression 10ba2if b6 and a2.?

To evaluate the expression ( 10ba^2 \cdot b^6 \cdot a^2 ), first combine the like terms. The ( b ) terms can be combined as ( b^{1+6} = b^7 ), and the ( a ) terms as ( a^{2+2} = a^4 ). Thus, the expression simplifies to ( 10b^7a^4 ).


What is the factor expression for a2-5a-14?

a2-5a-14 = (a-7)(a+2) when factored


How do you write a2-18b in verbal expression?

It is "a squared minus eighteen b".


What does a2 plus 2a2 equal?

The expression ( a^2 + 2a^2 ) can be simplified by combining like terms. Since both terms contain ( a^2 ), you add their coefficients: ( 1 + 2 = 3 ). Therefore, ( a^2 + 2a^2 = 3a^2 ).


If a2 b10 and c-4 then what is an expression that equals -2?

(A+C)-B


What is the simplified expression for 2a2b a2 5ab 3ab2 b2 2(a2b 2ab)?

To simplify the expression (2a^2b + a^2 + 5ab + 3ab^2 + b^2 + 2(a^2b + 2ab)), first distribute the 2 in the last term to get (2a^2b + 4ab). Combining like terms, we group all terms with (a^2b), (ab), (ab^2), and constant terms. The final simplified expression is (3a^2b + 9ab + 3ab^2 + b^2).


How do you factor the expression a2 4a 4-b2?

(a - b + 2)(a + b + 2)


What does a2 plus ab equals h2 mean?

It is an expression and a term that are of equal value


How do you factor trinomial squares?

First you would see is there is a Greatest Common Factor. Then you would factor the difference of squares binomial. After factoring out the GCF, the square root of the first term is 'a' and the square root of the second term is 'b'. Once 'a' and 'b' are found, substitute them into the binomial factors (a + b)(a - b).


How do you factor a2 10a-21?

The expression is faulty because we don't have + or - before 10a. Also have to assume a2 is a2 . Use the standard formula for solving a quadratic = 0, to get two answers p and q. Then the factorization is (a-p)(a-q).


How do you do two terms raised to third cube?

a3 - b3 = (a - b)(a2 + ab + b2) a3 + b3 = (a + b)(a2 - ab + b2)


For each integer a if a2-1 is even then 4 divides a2-1?

Assuming it's a2-1 you mean. If a2-1 is even, it can be expressed as a2-1 = 2 * t, where t is a natural number. a2-1 = (a - 1)(a + 1) = 2 * t You immediately see that at least one of the terms in parenthesis has to be even, and then, that actually both have to be even, because (a + 1) - (a - 1) = 2. Therefore, you can express both of the terms as: a - 1 = 2 * s a + 1 = 2 *r, which gives us: 2 * s * 2 * r = a2 - 1, simplify: 4 * r * s = a2 - 1. Therefore, if a2-1 is even, a2-1 is also divisible by 4.