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It is "a squared minus eighteen b".
The expression is faulty because we don't have + or - before 10a. Also have to assume a2 is a2 . Use the standard formula for solving a quadratic = 0, to get two answers p and q. Then the factorization is (a-p)(a-q).
2AB
Assuming it's a2-1 you mean. If a2-1 is even, it can be expressed as a2-1 = 2 * t, where t is a natural number. a2-1 = (a - 1)(a + 1) = 2 * t You immediately see that at least one of the terms in parenthesis has to be even, and then, that actually both have to be even, because (a + 1) - (a - 1) = 2. Therefore, you can express both of the terms as: a - 1 = 2 * s a + 1 = 2 *r, which gives us: 2 * s * 2 * r = a2 - 1, simplify: 4 * r * s = a2 - 1. Therefore, if a2-1 is even, a2-1 is also divisible by 4.
2 a2 is a monomial, not a binomial but 2 + a2 is a binomial, so is 2 - a2 .
a2-5a-14 = (a-7)(a+2) when factored
It is "a squared minus eighteen b".
(A+C)-B
(a - b + 2)(a + b + 2)
It is an expression and a term that are of equal value
It's an expression that can't be simplified.
The expression is faulty because we don't have + or - before 10a. Also have to assume a2 is a2 . Use the standard formula for solving a quadratic = 0, to get two answers p and q. Then the factorization is (a-p)(a-q).
a3 - b3 = (a - b)(a2 + ab + b2) a3 + b3 = (a + b)(a2 - ab + b2)
First you would see is there is a Greatest Common Factor. Then you would factor the difference of squares binomial. After factoring out the GCF, the square root of the first term is 'a' and the square root of the second term is 'b'. Once 'a' and 'b' are found, substitute them into the binomial factors (a + b)(a - b).
2AB
If you take the common term 4a out of the expression 16a4 + 4a3, you get 4a(4a3 + a2), making it apparent that if you divide by 4a, the quotient is (4a3 + a2).
int x = 2 * (a + b);