You can wind up with 10 different pairs of books in your hand, which
you can choose from a shelf of 5 books in 20 different ways.
240. 120 ways with the books stacked verticly, and 120 ways with the books stacked horizontaly, or one on top of the other.
120. You do 5*4*3*2*1=120. you multiply the number that you are given for example how many times can books 3 be arranged on a shelf you multiply 3*2*1=6 that is your answer
Answerthe answer is 24 WHICH is the result of the multiplication: 4x 3 x 2 x 1 = 24. You can try it practically as: Numbering books as A,B, C, and D then the variations are:ABCDABDCBACDBADCCDABCDBADCABDCBABCADBCDACBADCBDAADBCADCBDABCDACBBDACBDCADBACDBCAACBDACDBCABDCADB
8 ! = 8 X 7 X 6 X 5 X 4 X 3 X 2 X 1 = 40320
35
792 different groups of 5 books, in 95,040 different sequences.
Choose 3 then 2 then 1; 3*2*1 = 6 ways.
20, without replacing the first book chosen. 25 with replacing it.
There are 8 ways to choose the first book There are 7 ways to choose the second book - 8 x 7 = 56 ways to select two books There are 6 ways to choose the third book - 8 x 7 x 6 = 336 way to select three books There are 5 ways to choose the fourth book - 8 x 7 x 6 x 5 = 1,680 ways to select four books.
it depends on the shelf of course
6 ways
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30 ways.
There are only 5 places on the shelf. You have 7 books to choose from. We will ignore the order of the books on the shelf. The first place can be filled from a choice of 7 books, the next place from 6, the next place from 5, the next from 4, and the last of the 5 places from 3 books. So the number of ways of choosing the 5 is found from 7 * 6 * 5 * 4 * 3 = 2520
24 ways
There are 2*5! = 240 ways.
240. 120 ways with the books stacked verticly, and 120 ways with the books stacked horizontaly, or one on top of the other.