90000
To arrange 24 students in 3 rows, we first need to determine how many students will be in each row. Assuming an equal distribution, we can place 8 students in each row. The total number of arrangements can be calculated by dividing the arrangements of all 24 students (24!) by the arrangements within each row (8! for each row). Therefore, the total number of ways to arrange the students is given by the formula: ( \frac{24!}{(8!)^3} ).
To determine the number of ways the farmer can arrange 189 plants in rows of 9, we first divide 189 by 9, which gives us 21 rows. The number of ways to arrange the 189 plants in these rows depends on how the plants are differentiated. If all plants are identical, there's only one way to arrange them. However, if the plants are distinct, the number of arrangements would be 189! (189 factorial).
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
There are 1860480 ways.
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
8
4
You can have: 1 row of 36 2 rows of 18 3 rows of 12 4 rows of 9 or 6 rows of 6, so in total there are 5 ways.
To determine the number of ways the farmer can arrange 189 plants in rows of 9, we first divide 189 by 9, which gives us 21 rows. The number of ways to arrange the 189 plants in these rows depends on how the plants are differentiated. If all plants are identical, there's only one way to arrange them. However, if the plants are distinct, the number of arrangements would be 189! (189 factorial).
Oh, dude, arranging 6 counters in equal rows is like a puzzle, man. So, if you're into math and stuff, there are 720 different ways you can do it. But hey, who's counting, right? Just go with the flow and arrange those counters however you like.
Two ways only. 4 rows with 25 stamps each or 5 rows with 20 stamps each.
There are 1860480 ways.
The number of ways to arrange six students in a lunch line can be calculated using the factorial of the number of students. Specifically, this is 6! (6 factorial), which equals 6 × 5 × 4 × 3 × 2 × 1 = 720. Therefore, there are 720 different ways to arrange six students in a lunch line.
2 rows of 18 squares3 rows of 12 squares4 rows of 9 squares6 rows of 6 squares9 rows of 4 squares12 rows of 3 squares18 rows of 2 squares36 rows of 1 squareI would not count "1 row of 36 squares", because you only have a single row that cannot equal another row (there is only one rowafter all). If this is for homework, I would state your reasoning for excluding (or including) that set. Count all the options up, and you have 8 different ways you can arrange the rows with the exclusion.
Oh, what a happy little question! If you have 32 tiles and want to arrange them in equal rows and columns, you could have 1 row of 32 tiles, 2 rows of 16 tiles, 4 rows of 8 tiles, 8 rows of 4 tiles, or 16 rows of 2 tiles. Each arrangement brings its own unique beauty to the canvas of possibilities. Just remember, there are many ways to create a masterpiece with those tiles!
You can arrange 6 counters in equal rows in three ways: 1 row of 6, 2 rows of 3, and 3 rows of 2. This is determined by finding the divisors of 6, which are the numbers that can evenly divide 6, leading to these arrangements. Each arrangement corresponds to a different divisor: 1, 2, 3, and 6. Thus, the total number of arrangements is based on these divisors.
To determine how many ways a teacher can arrange 5 students in the front row from a total of 23 students, we use permutations since the order matters. The number of ways to choose and arrange 5 students from 23 is given by the formula ( P(n, k) = \frac{n!}{(n-k)!} ), where ( n ) is the total number of students and ( k ) is the number of students to arrange. Thus, it is calculated as ( P(23, 5) = \frac{23!}{(23-5)!} = \frac{23!}{18!} = 23 \times 22 \times 21 \times 20 \times 19 = 2,598,960 ). Therefore, there are 2,598,960 different ways to arrange 5 students in the front row.