If the angle of elevation is 32 degrees then using the tangent ratio in trigonometry the height of the tree is 18.75 feet rounded up to two decimal places
It is approx 18.7 metres high.
10.08 feet approx.
The shadow:object ratio is 1:1 so the tree is 63 feet high.
Ratio of object to its shadow is the same. So if T is the height of the tree, then T/21 = 4/6 So T = 21*4/6 = 84/6 = 14 feet
The ratios are in the same proportion, so all you need to really figure out is what is in the same ratio to 20 as 6 is to 4.
27.3 feet
It is nearly 40 feet
36 degrees
Use the tangent ratio: tan = 93/26 = 74.38 degrees to 2 d.p.
Your missing the angle of elevation or depression.
It depends on the time of day because the angle of the sun will determine the shadow length
Angle of elevation = 300/50 = 6 tan-1(6) = 80.53767779 degrees or 800 32' 15.64''
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
2
The man is 5.96 feet tall and the lamp is 17.88 feet high.
51
If you mean the height of the building then it works out as 466.5063509 feet
28 feet