58.5
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
15 units
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
They bisect one another.
31.5 Square Units
31.5
38.5 Square units
38.5
The area of a rhombus can be calculated using the formula: Area = (1/2) × d1 × d2, where d1 and d2 are the lengths of the diagonals. In this case, AC (d1) is 9 and BD (d2) is 13. Therefore, the area = (1/2) × 9 × 13 = 58.5 square units.
31.5 square units
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
84
A rhombus has two lines of symmetry. They are also called its diagonals. Suppose there is a rhombus ABCD AC and BD are its lines of symmetry.
15 units
5 units