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What is the area of rhombus ABCD if AC equals 8 and BD equals 9?
A = (1/2)(ac)(bd) = (1/2)(8)(9) = 36
What is the area of rhombus ABCD if AC 7 and BD 12?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
In rhombus abcd bd equals 18 ac equals 24 what is the length of each side?
15 units
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
If ABCD is a parallelogram what can we say about the diagonals BD and AC?
They bisect one another.
