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What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
Wiki User
∙ 13y ago
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:
Area = (1/2) * ( 12 * 7) = 42.
The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.
The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.
So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
Wiki User
∙ 13y ago
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What is the area of rhombus ABCD if AC 7 and BD 12?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals: Area = (1/2) * ( 12 * 7) = 42.
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