5 [3-4-5 triangle]
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This problem can be solved using the Sine Rule :a/sin A = b/sin B = c/sin C 10/sin 45 = AB/sin 75 : AB = 10sin 75 ÷ sin 45 = 13.66 units (2dp)
The length of ab can be found by using the Pythagorean theorem. The length of ab is equal to the square root of (0-8)^2 + (0-2)^2 which is equal to the square root of 68. Therefore, the length of ab is equal to 8.24.
Using the distance formula the length of ab is 5 units
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Using Pythagoras Length AB = √((-8 - 2)² + (4 - -4)²) = √(6² + 8²) = √100 = 10 units.