The first thing to do is to find the equation of the line. A line, m, that is perpendicular to another line, k, always has a slope that is the opposite of the inverse of the slope of the second line, k. In this case, the line I've named k has a slope of 2. So the slope of the line we need, which I've named m, will be the opposite of the inverse, which is -1/2. To get the y- intercept, plug in the point you already have and solve.
y=mx+b
3=(-1/2)4+b
3=-2+b
5=b
So the y-intercept for m is 5, giving us the equation for m, which is y=(-1/2)x+5. Now just substitute the second point and solve.
h=(-1/2)2+5
h=-1+5
h=4
The point is (2,4), and so h is 4.
-10 over 4 i think...
The slope of a line that passes through two points is (difference in y) / (difference in x).
It is a line that passes through or nearly passes through the plotted points on the coordinated grid.
No
5/6
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
-10 over 4 i think...
y=-x
Where are the points!
The slope of a line that passes through two points is (difference in y) / (difference in x).
The origin and infinitely many other points of the form (x, ax) where x is any real number.
It is a line that passes through or nearly passes through the plotted points on the coordinated grid.
No, because the second line is not defined.
there are 6 lines can pass through 4 noncollinear points.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
y - 2 = 0
It is a chord.