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If the complement of an angle is five times the measure of the angle itself find the angle and its complement?
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An angle is five times its complement find its measure?
Suppose the angle is x degrees. Then its complement is x/5 deg So x + x/5 = 90 or 6x = 450 ie x = 75 degrees.
If a angle of thirty five degree's and seventy five degree's then what is the measure of the third angle?
You know, if you look in your math book, it'll tell you how to find out. Alternatively, you could just pay attention in class.
In triangle pqr the measure of angle p is 36 degrees the measure of angle q is five times the measure of angle r find angle q and angle r?
Sum of all three angles is 180 degrees. p = 36 so q+r = 180-36 = 144 degrees. Now, q = 5r so 144 = q+r = 5r+r = 6r so r = 144/6 = 24 and then q = 5r = 5*24=120 Answer: q = 120 deg, r = 24 deg
How many degrees in a seven sided shape?
You work out the sum of the inside angles by taking the number of sides of the shape minus two, then multiplying that by 180. For example, a quadrilateral has four sides, so you take away two from four and get two. Multiply two by 180 and you get 360˚. For each inside angle, if it is regular (a square) divide 360 by four (the number of angles) and you get 90˚. For an outside angle, do 360 (the degrees of a full circle) minus 90 (inside angle). You get 270˚. The sum of the outside angles is then 270 times four - 1080˚. Get the idea? So, a seven sided shape has seven sides (duh). Minus two is five. Five times 180 is 900˚. If it is a regular shape, divide 900 by seven (it isn't a whole number - sorry), and that is one inside angle. If you want the OUTSIDE angles, find each inside angle then take that away from 360. Times by seven for the sum of the outside angles. This was a very long way of explaining, but I didn't know what type of angle you wanted! Hope it makes sense!!! ;)
