Final solution, x = 2 ----- WORK -----
(5, -3) (X2, 1)
(X1, Y1) (X2, Y2)
D = SQRT( [X1 - X2]2 + [Y1 - Y2]2 )
5 = SQRT( [5 - X2]2 + [-3 - 1]2 )
5 = SQRT( [5 - X2]2 + (-4)2 )
5 = SQRT( [5 - X2]2 + 16 )
Since The square root of 25 is 5, we know that ->
[5 - X2]2 + 16 = 25
Subtract 16 from both sides,
[5 - X2]2 = 9
Which means that 5-X2 = 3 Because 32 is 9
5 - X2 = 3
subtract 5 from both sides
-X2 = -2
multiply both sides by -1
X2 = 2
There you go...
X2 = 2
(5, -3) (2, 5)
The distance between the points of (4, 3) and (0, 3) is 4 units
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
The perpendicular distance is the shortest.
The ant is at (-0.2794, 0.9602)
Yes
The distance between the points of (4, 3) and (0, 3) is 4 units
The answer is the x coordinate of the point.
The distance between the points of (4, 3) and (0, 3) is 4 units
The horizontal distance between them is from -5 to 1, that is 6 units. The vertical distance between them is from 1 to 6, that is 5 units. So, using Pythagoras, the distance between then, along the diagonal, is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) units.
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Since they are the same point, the distance between them is 0.
The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.
Different units for measuring distance are: 1.for distances on earth miles , kilometer, meter 2. Between galaxies - light year.
Well, let's imagine a peaceful little point at coordinates -3, 4. To find its distance from the x-axis, we just need to look at how far up or down it is. Since the point is 4 units above the x-axis, that's its distance. Just a happy little calculation to show how everything has its place in the world.
If the two lines are parallel, then the shortest distance between them is a single, fixed quantity. It is the distance between any point on one line along the perpendicular to the line.Now consider the situation where the two lines meet at a point X, at an angle 2y degrees. Suppose you wish to find points on the lines such that the shortest distance between them is 2d units. [The reason for using multiples of 2 is that it avoids fractions].The points are at a distance d*cos(y) from X, along each of the two lines.
Modulus units in mathematics are used to measure the distance between two points on a number line or to find the remainder when dividing two numbers.
To find the distance between two integers using the difference, you simply subtract the smaller integer from the larger integer. The result will be the distance between the two integers on the number line. For example, if you have integers 7 and 3, you would subtract 3 from 7 to get a distance of 4. This method works because the difference between two integers gives you the number of units separating them on the number line.