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If the distance between the point 5-3 and x 1 is 5 units find x?
Wiki User
∙ 15y ago
Final solution, x = 2 ----- WORK -----
(5, -3) (X2, 1)
(X1, Y1) (X2, Y2)
D = SQRT( [X1 - X2]2 + [Y1 - Y2]2 )
5 = SQRT( [5 - X2]2 + [-3 - 1]2 )
5 = SQRT( [5 - X2]2 + (-4)2 )
5 = SQRT( [5 - X2]2 + 16 )
Since The square root of 25 is 5, we know that ->
[5 - X2]2 + 16 = 25
Subtract 16 from both sides,
[5 - X2]2 = 9
Which means that 5-X2 = 3 Because 32 is 9
5 - X2 = 3
subtract 5 from both sides
-X2 = -2
multiply both sides by -1
X2 = 2
There you go...
X2 = 2
(5, -3) (2, 5)
Wiki User
∙ 15y ago
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