Final solution, x = 2 ----- WORK -----
(5, -3) (X2, 1)
(X1, Y1) (X2, Y2)
D = SQRT( [X1 - X2]2 + [Y1 - Y2]2 )
5 = SQRT( [5 - X2]2 + [-3 - 1]2 )
5 = SQRT( [5 - X2]2 + (-4)2 )
5 = SQRT( [5 - X2]2 + 16 )
Since The square root of 25 is 5, we know that ->
[5 - X2]2 + 16 = 25
Subtract 16 from both sides,
[5 - X2]2 = 9
Which means that 5-X2 = 3 Because 32 is 9
5 - X2 = 3
subtract 5 from both sides
-X2 = -2
multiply both sides by -1
X2 = 2
There you go...
X2 = 2
(5, -3) (2, 5)
The distance between the points of (4, 3) and (0, 3) is 4 units
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
The perpendicular distance is the shortest.
The ant is at (-0.2794, 0.9602)
Yes
The distance between the points of (4, 3) and (0, 3) is 4 units
The answer is the x coordinate of the point.
To find the distance between the points -64 and 34, subtract the smaller number from the larger number. The calculation is |34 - (-64)|, which simplifies to |34 + 64| = |98|. Therefore, the distance between the two points is 98 units.
The distance between the points of (4, 3) and (0, 3) is 4 units
The horizontal distance between them is from -5 to 1, that is 6 units. The vertical distance between them is from 1 to 6, that is 5 units. So, using Pythagoras, the distance between then, along the diagonal, is sqrt(62 + 52) = sqrt(36 + 25) = sqrt(61) units.
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Since they are the same point, the distance between them is 0.
The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.
Different units for measuring distance are: 1.for distances on earth miles , kilometer, meter 2. Between galaxies - light year.
Well, let's imagine a peaceful little point at coordinates -3, 4. To find its distance from the x-axis, we just need to look at how far up or down it is. Since the point is 4 units above the x-axis, that's its distance. Just a happy little calculation to show how everything has its place in the world.
If the two lines are parallel, then the shortest distance between them is a single, fixed quantity. It is the distance between any point on one line along the perpendicular to the line.Now consider the situation where the two lines meet at a point X, at an angle 2y degrees. Suppose you wish to find points on the lines such that the shortest distance between them is 2d units. [The reason for using multiples of 2 is that it avoids fractions].The points are at a distance d*cos(y) from X, along each of the two lines.
Modulus units in mathematics are used to measure the distance between two points on a number line or to find the remainder when dividing two numbers.