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Well, let's imagine a peaceful little point at coordinates -3, 4. To find its distance from the x-axis, we just need to look at how far up or down it is. Since the point is 4 units above the x-axis, that's its distance. Just a happy little calculation to show how everything has its place in the world.
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What will be the coordinates of point which lie on y axis at a distance of 4 units in negative direction of x axis?
The unclear information given suggests that the coordinate is (-4, 0)
How do you mark any 4 points on a coordinate grid so that each point is the same distance from the y-axis?
move to the left or right of the y- axis the given distance. place points there. move up any distance. then move to the left or right of the y- axis the given distance. place points there. now you have 4 points
What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?
Circle equation: x^2 +y^2 -2x -6y +5 = 0 Completing the squares: (x-1)^2 +(y-3)^2 = 5 Centre of circle: (1, 3) Tangent line meets the x-axis at: (0, 5) Distance from (0, 5) to (1, 3) = 5 units using the distance formula
Do you travel along on an axis graph and then up?
The answer depends on the coordinates of the point that you wish to get to. If it is (3, -4), then NO, but if it is (3, 4) then YES.
How do you make a graph from points?
Let us consider a point (3,4). Now, the number written first is the x-coordinate and the next number is the y-coordinate. The x-axis of a graph is the horizontal line and the y-axis is the vertical line. the x-coordinates are plotted taking the x-axis for reference and the y-coordinates are plotted taking the y-axis as reference. So now, if we have the point (3,4) then we see the x-axis to see where the x-coordinate is. We have 3 as x-coordinate. Just keep a mental note of where the "3" is on the x-axis. then see the y-xis and try to find out where the y-coordinate is (In this case, 4). daw a horizontal line from 4 in the y-axis and a vertical line from 3 in the x-axis. These two lines meet a point. this point is the point we had to plot i.e., (3,4). If you observe the graph so plotted, you will see that (3,4) is at a distance of 3 units from the origin along the x-axis and 4 units from the origin along the y-axis.
What is the distance to the center of the circle x2 plus y2 -2x -6y plus 5 equals 0 from the x axis at the same point when the tangent line meets the x axis from the point 3 4?
Equation of circle: x^2 +y^2 -2x -6y +5 = 0 Completing the squares: (x-1)^2 +(y-3)^2 = 5 Center of circle: (1, 3) Tangent line from (3, 4) meets the x axis at: (5, 0) Distance from (5, 0) to (1, 3) = 5 using the distance formula
What will be the coordinates of point which lie on y axis at a distance of 4 units in negative direction of x axis?
The unclear information given suggests that the coordinate is (-4, 0)
Find the co-ordinate of points on the x-axis which are at a distance of 5 units from the point (6,-3)?
To find the coordinates of points on the x-axis that are 5 units away from the point (6, -3), we can use the distance formula. The distance formula is: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, we know that x1 = 6, y1 = -3, and distance = 5. We also know that the points are on the x-axis, so the y-coordinate is 0. So we can plug these values into the distance formula and solve for x2: 5 = √((x2 - 6)^2 + (0 - (-3))^2) 5 = √(x2 - 6)^2 + 9 25 = (x2 - 6)^2 x2 = √25 + 6 = √16 + 6 = 4 + 6 = 10 Therefore, the coordinates of the point on the x-axis that is 5 units away from (6, -3) in the positive direction of x-axis are (10, 0) and the point on the x-axis that is 5 units away from (6, -3) in the negative direction of x-axis is (2,0).
What is the value of moment of inertia of ellipse about x-Axis?
The moment of inertia of an ellipse about its major axis (x-axis) is given by the equation I = πab^3/4, where a is the length of the semi-major axis and b is the length of the semi-minor axis of the ellipse.
How do you mark any 4 points on a coordinate grid so that each point is the same distance from the y-axis?
move to the left or right of the y- axis the given distance. place points there. move up any distance. then move to the left or right of the y- axis the given distance. place points there. now you have 4 points
What is the distance from a point on the x axis to the centre of a circle when a tangent line at the point 3 4 meets the circle of x2 plus y2 -2x -6y plus 5 equals 0?
Circle equation: x^2 +y^2 -2x -6y +5 = 0 Completing the squares: (x-1)^2 +(y-3)^2 = 5 Centre of circle: (1, 3) Tangent line meets the x-axis at: (0, 5) Distance from (0, 5) to (1, 3) = 5 units using the distance formula
Do you travel along on an axis graph and then up?
The answer depends on the coordinates of the point that you wish to get to. If it is (3, -4), then NO, but if it is (3, 4) then YES.
Is the point -3-4 located above below or on the x-axis?
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How do you make a graph from points?
Let us consider a point (3,4). Now, the number written first is the x-coordinate and the next number is the y-coordinate. The x-axis of a graph is the horizontal line and the y-axis is the vertical line. the x-coordinates are plotted taking the x-axis for reference and the y-coordinates are plotted taking the y-axis as reference. So now, if we have the point (3,4) then we see the x-axis to see where the x-coordinate is. We have 3 as x-coordinate. Just keep a mental note of where the "3" is on the x-axis. then see the y-xis and try to find out where the y-coordinate is (In this case, 4). daw a horizontal line from 4 in the y-axis and a vertical line from 3 in the x-axis. These two lines meet a point. this point is the point we had to plot i.e., (3,4). If you observe the graph so plotted, you will see that (3,4) is at a distance of 3 units from the origin along the x-axis and 4 units from the origin along the y-axis.
The gradient of the line y equals 4 plus 3 is?
Zero, the line is parallel to the x-axis at a distance 4+3 = 7
What is the distance from point M (3 2) to point N (3 4)?
The distance is 2, along the x-value line x=3 i.e. (3, y).
What is the distance from a point on the x axis to the centre of the circle x2 plus y2 -2x -6y plus 5 equals 0 from the same point where a tangent line meets the circle at 3 4?
Equation of circle: x^2 +y^2 -2x -6y +5 = 0 Completing the squares: (x -1)^2 +(y -3)^2 = 5 which is radius squared Center of circle: (1, 3) Tangent line is at right angles to the radius at (3, 4) and meets the x axis at (5, 0) Distance from point (5, 0) to center of circle (1, 3) = 5 units using distance formula
