Take each row and convert it into a column. The first row becomes the first column, the second row, the second column, etc.
true
by 2 rows
8 rows of 6 students 6 rows of 8 students 4 rows of 12 students 3 rows of 16 students 2 rows of 24 students 1 row of 48 students
Oh, dude, arranging 6 counters in equal rows is like a puzzle, man. So, if you're into math and stuff, there are 720 different ways you can do it. But hey, who's counting, right? Just go with the flow and arrange those counters however you like.
Each element of a row of pascal's triangle is the sum of the two elements above it. Therefore when you some the elements of a row, each of the elements of the row above are being summed twice. Thus the sum of each row of pascal's triangle is twice the sum of the previous row.
The Fifth row of Pascal's triangle has 1,4,6,4,1. The sum is 16.
The sum of the numbers in each row of Pascal's triangle is twice the sum of the previous row. Perhaps you can work it out from there. (Basically, you should use powers of 2.)
The sum of the numbers on the fifteenth row of Pascal's triangle is 215 = 32768.
The sum of the numbers in the nth row of Pascal's triangle is equal to 2^n. Therefore, the sum of the numbers in the 100th row of Pascal's triangle would be 2^100. This formula is derived from the properties of Pascal's triangle, where each number is a combination of the two numbers above it.
No. It's n^2
When evaluating row n+1 of Pascal's triangle, each number from row n is used twice: each number from row ncontributes to the two numbers diagonally below it, to its left and right. From this it is easily seen that the sum total of row n+1 is twice that of row n. The first row of Pascal's triangle, containing only the single '1', is considered to be row zero. Its total, 1, is given by 20. From the above observations, we can conclude that the total of row n is given by 2n. For the eleventh row: 211 = 2048.
7
the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc.......... the horizontal sums doubles each time the sum of row 1 = 1 row 2= 2 row 3 = 4 row 4 = 8 row 5 = 16 etc etc..........
If the top row of Pascal's triangle is "1 1", then the nth row of Pascals triangle consists of the coefficients of x in the expansion of (1 + x)n.
1,429,144,287,220
64