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What is the Square root of -1 Times Square root of -1?
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Square root of one half?
Square root of 1/2 = (1)/(square root of 2) = 1/1.4142 = 0.7071 Also Square root of 1/2 = Square root of 0.5 = 0.7071
What is the square root of x squared plus 1?
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
How do you solve x2 - 4x 1 0 by completing the square?
x2 + 4x + 1 = 0 add and subtract 3 to both sides to complete the square x2 + 4x + 4 = 3 form the square (x + 2)2 = 3 take the square root of both sides x + 2 = ± √3 subtract 2 to both sides x = -2 ± √3
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
Integrate square root of 4 xdivide by x?
∫[√(4x) / x] dx = ∫(2 / √x)dx = 2∫(x-1/2) dx = 2(2x1/2 + C) = 4√x + C
How do you integrate square root of 1 over x-1 dx?
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What is the derivative of y equals square root of 8x plus square root of 4x?
y=(8x).5 + (4x).5 = (2+2sqrt(2))x.5 y'=(1 + sqrt(2))/sqrt(x)
Choose the quadratic equation with a leading coefficient of 1 that has as solutions -2 plus 3 square root 5 and -2 -3 square root 5?
x2 + 4x = 41
How do you factor 4x2-20x plus 25?
16x2 + 27x - 28 doesn't factor. Applying the quadratic formula, we find two real solutions:(-27 plus or minus the square root of 2521) divided by 32x = 0.725298776329149x = -2.412798776329149
Which is the solution set for x2 - 4x 8?
x = 2 + 2ix = 2 - 2iwhere i is the imaginary square root of -1.
What is the sqare root of both sides 4x²-8x plus 4 equals 56?
The square root of the left hand side is 2*(x - 1).The square root of the right hand side is 2*sqrt(14)
X2 plus 4x-1 equals 0?
Using the quadratic equation formula the values of x are: x = -2 - the square root of 5 and also x = -2 + the square root of 5
Can you solve the equation 4x squared plus 7 equals 5?
Yes, but the solution is imaginary if you have learned that 4x^2 + 7 = 5 4x^2 = -2 x^2 = -1/2 x = +/-0.707i where i = square root of -1
X over x plus 1 equals 4over x plus 4?
x ............... 4_____ = ______x + 1 ....... x + 4x(x + 4) = 4(x + 1)x2 + 4x = 4x + 4and sox2 = 4 ,,, take the root square for boththe result will bex = ±2
What is the Square root of -1 Times Square root of -1?
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How do you Factorise this 12x square 7x plus 1?
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
