Divide all terms by 3 so:- x2-4x = 5 Completing the square:- (x-2)2 = 9 x-2 = -/+3 x = -1 or x = 5
the problem is not proper to slove. I just want to suggest to follow the related link that explains the concept of completing the square clearly.
No because the discriminant of the given quadratic expression is less than zero.
4x-x2 = 2
x2 + 20x +0 =30 [(20/2)2 =100] x2 + 20x + 100 =30 +100 √(x+10)2=√130 x+10=√130 x= −10+√130 √ means square root
x2 - 4x - 9 = 0 ∴ x2 - 4x = 9 ∴ x2 - 4x + 4 = 13 ∴ (x - 2)2 = 13 ∴ x - 2 = ±√13 ∴ x = 2 ± √13
Divide all terms by 3 so:- x2-4x = 5 Completing the square:- (x-2)2 = 9 x-2 = -/+3 x = -1 or x = 5
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
the problem is not proper to slove. I just want to suggest to follow the related link that explains the concept of completing the square clearly.
If you aren't dealing with algebra, such as x2+3x+21, then completing the square wont be able to solve the porblem, however if you are using algebra, and you cannot factorise, then completing the square will always work
x2-4x-21 = 0 => x = -3 or x = 7 x2-3x-18 = 0 => x = -3 or x = 6
X(X2 - X)
x2 + 4x + 6 can not be factored. If you want, you can reduce it to an expression with a single x term by comleting the square: x2 + 4x + 6 = x2 + 4x + 4 + 2 = (x + 2)2 + 2
No because the discriminant of the given quadratic expression is less than zero.
X2= 4x + 5 solve for X
x2 + 4x = 1 x2 + 4x - 1 = 0 in the quadratic formula (b2+- Sqr(4ac))/2a, a = 1 b = 4 c = -1 so x = 8 +- i
x2 + 4x - 3 = 0 add 3 to both sides x2 + 4x = 3 add 22 to both sides to complete the square x2 + 4x + 22 = 7 form the square (x + 2)2 = 7 take the square root of both sides x + 2 = ± √7 subtract 2 to both sides x = -2 ± √7 x = -2 + √7 or x = -2 - √7