If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
1
If you mean: y = x+4 and y = 3x+8 then x = -2 and y = 2
The mathematical symbols did not appear so I am assuming that your question is if the point (-1,-1) is a solution of y = 3x + 2, in that case, substitute -1 for y and -1 for x and you get -1 = 3(-1) + 2 or -1 = -3 + 2 or -1 = -1 Thus if I assumed the question correctly, then -1,-1 is a solution to y = 3x + 2
If you mean: y = 3x-3 and (-2, 1) then it is y = 3x+7
If you mean y = 3x+2 then (-1, -1) is a solution of the given straight line equation
No.
Yes, it is.
The mathematical symbols did not appear so I am assuming that your question is if the point (-1,-1) is a solution of y = 3x + 2, in that case, substitute -1 for y and -1 for x and you get -1 = 3(-1) + 2 or -1 = -3 + 2 or -1 = -1 Thus if I assumed the question correctly, then -1,-1 is a solution to y = 3x + 2
If: y = 3x+4 and y = 2-7x Then: 3x+4 = 2-7x So: 3x+7x = 2-4 => 10x = -2 => x = -1/5 By substitution: y = 17/5 Solution: x = -1/5 and y = 17/5
y = 2 sin 3x y' = 2(sin 3x)'(3x)' y' = 2(cos 3x)(3) y' = 6 cos 3x
If you mean (1) y + 3x = 22 and (2) y + 2x = 16, then (1) y = 22 - 3x (sub this into (2)) (2) (22 - 3x) + 2x = 16 -x = -6 x = 6 y = 22 - 3x = 22 -3(6) = 4 solution: (6,4)
-4
x=1, y=5 is a legitimate answer.
1
YES ! When x = -1 then y = 3(-1) + 2 = -3 + 2 = -1
If you mean: y = 3x+2 then (-1, -1) will satisfy the straight line equation