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I understand the equation to be y = -3x - 2 and the point to be (5,1).
I substitute 1 for each appearance of y and 5 for each appearance of x:
1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution.
To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears:
y = -3(1) - 2 = -3 - 2 = -5.
Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
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What is the solution for Y equals x-2 and 2x plus y equals 1?
The solution is: x = 1 and y = -1
What is the solution of the system -x plus y equals 4 and x plus y equals 2?
It is (-1, 3).
What is the solution for y equals 1 y equals -4x and y equals -12x?
1). y = 12). y = -4x3). y = -12xA "solution" is a pair of numbers ... one for 'x' and one for 'y' ... that makes the statements true.There is no solution for the group of all three equations.The solution for #1 and #2 taken together is (-1/4 , 1).The solution for #1 and #3 taken together is (-1/12 , 1).The solution for #2 and #3 taken together is (0, 0).
When are y equals sin x and y equals cos x times cos x equal?
y=sin x y=cos x cos x sin x = cos^2 x sin x = 1-sin^2 x sin x -1 + sin^2 x = 0 sin^2 x + sin x -1 = 0 Let y=sin x y^2+y-1 = 0 This equation is of form ay^2+by+c=0 a = 1 b = 1 c = -1 y=[-b+/-sqrt(b^2-4ac)]/2a] y=[-1 +/-sqrt(1^2-4(1)(-1)]/(2)(1) discriminant is b^2-4ac =5 y=[-1 +√(5)] / 2 y=[-1 -√(5)] / 2 sin x = [-1 +√(5)] / 2 x = sin^-1 [-1 +√(5)] / 2] = 0.6662394 radians x = sin^-1 [-1 -√(5)] / 2] = sin^-1 (-1.618) -- has no solution When x = 0.6662394 radians, sin x and cos x times cos x are equal.
The vertex of this parabola is at (-2, -3) When the x-value is -1, the?
Y=a(x-h)+k is the vertex formula. Since the vertex is at (-2,-3) this parabola has the equation: y=a(x+2)^2-3 We can plug in x=-1 but we really need to know a, to solve for y. ( we can solve it, but we will have an a in the solution)
What is the solution for Y equals x-2 and 2x plus y equals 1?
The solution is: x = 1 and y = -1
Is 1 and 2 a solution to Y equals 2x?
If by that you mean x= 1 and y= 2 then yes (1,2) is a solution
Is 2 and 1 a solution to y equals x plus 1?
Yes, since (1,2) satisfies y = x + 1 y = (1) + 1 y = 2 and 2 = 2
How many solutions are in y equals -2x y equals 3x plus 5?
There is one solution for x and one solution for y. The solution is: x = -1 ; y = 2
Is there a no solution in y equals x-1 and y equals -x plus 1?
In the equations Y=X-1 and Y=-X+1, the solution is (1,0)
Is (2 1) a solution to y x plus 1?
The mathematical symbols did not appear so I am assuming that your question is if the point (-1,-1) is a solution of y = 3x + 2, in that case, substitute -1 for y and -1 for x and you get -1 = 3(-1) + 2 or -1 = -3 + 2 or -1 = -1 Thus if I assumed the question correctly, then -1,-1 is a solution to y = 3x + 2
What is the solution to 2y equals x plus 2?
y = x + 1
What is a solution to y equals x plus 2?
y = 3, x = 1 y = 4, x = 2 Anything where y is two greater than x will work.
Is 5 1 a solution of y -3x - 2?
I understand the equation to be y = -3x - 2 and the point to be (5,1). I substitute 1 for each appearance of y and 5 for each appearance of x: 1 = -3(5) - 2 = -15 - 2 = -17, which is not a true statement. Therefore, that is not a solution. To get a solution, set x=1, and calculate y by substituting this value (1) for x wherever it appears: y = -3(1) - 2 = -3 - 2 = -5. Therefore, (-5,1) is a solution. (I suspect that this is what you meant to put in the question.)
Is 2 and 2 a solution to x equals y?
Yes if x=2 and y=2, then x=y
How do you solve y equals x plus 2?
There are infinitely many "solutions". In the Cartesian plane, the coordinates of any point on the line defined by y = x + 2 is a solution. Thus, any ordered pair, (x, x+2) is a solution.
The solution to the system of equations y equals 2x and y equals -x plus 3 is?
x = 1 and y = 2
