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Q: Is the point (0 2) a solution to the system y - x plus 6?

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12x+6y=9 - 1 4x+2y=0 - 2 y=-2x sub y= -2x into 1, 12x+6(-2x)=9 12x-12x=9 0=9 thus, no solution.

x+y=0 2x+2y=0 This homogeneous system has infinitely many non-trivial solutions. If you are looking for exactly one non-trivial solution, no such system exists. the system may or may not have non trivial solution. if number of variables equal to number of equations and given matrix is non singular then non trivial solution does not exist

When the solution is equal to a number, in other words, only one solution happens if you solve for your variables. 0 = 0 means there are many solutions and a number not equal to another number has no solution.

No, it has an infinite number of solutions. The coordinates of each and every point on the line 3x + 2y + 4 = 0 is a solution.

It means the coordinate (0, 0) - or in three dimensions, (0, 0, 0). That is, the origin, or starting point, of the coordinate system.

Related questions

It works out that x = 0 and y = 3

For (x, y) = (0, 3) the first equation gives: 2*0 + 3 = -3 that is, +3 = -3 which is FALSE. So (0, 3) is not a solution.

0 degree

(0, -14)

I) x>0 II) y>0 The first quadrant is the part of the coordinate plane where x and y are both positive. The above system states precisely that, and actually any point in the first quadrant is a solution to the above system of inequalities.

The solution to 40 plus 40 times 0 plus 1 is 41. The number name is forty-one.

That is not a correct equation. The numbers on the left equal -16, not 0. This is an equation with no solution.

x = 0

It is x = -5

True because in both equations x = 0 or x = -4

8

( 1 0 1 ) + ( 1 0 1 ) = 1 0 1 0

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