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What else can I help you with?
Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?
No, it is not a function.
Is (6 8) (-4 -1) (2 3) a function or a relation?
It is both.
How do you determine if you are given a set of ordered pairs that represent a function?
A relation is a set of ordered pairs.A function is a relation such that for each element there is one and only one second element.Example:{(1, 2), (4, 3), (6, 1), (5, 2)}This is a function because every ordered pair has a different first element.Example:{(1, 2), (5, 6), (7, 2), (1, 3)}This is a relation but not a function because when the first element is 1, the second element can be either 2 or 3.
Is (3 6) (1 6) (5 6) (8 6) a function or relation?
It is both.
How do you state the domain of this relation 5) (2 3) (1 -4) (-3 3) (-1 -2)?
If this is the whole of the function, then the domain is {2, 1, -3, -1}. That set can be put in increasing order if you wish but that is not necessary.
Is this relation a function{(0, 0), (1, 0), (2, 0), (3, 0), (4, 0)}?
yes
Is the relation (1 3) (4 0) (3 1) (0 4) (2 3) a function?
If those are the only values, no.
Is this relation afunction (-32)(2-4)(26)(-3-5)(0 3)?
No, it is not a function.
What are the kinds of relation in mathematics?
1. One to One -function- 2. One to Many -relation- 3. Many to Many -function-
How can you tell if a relation of a graph has a function?
A relation is any set of ordered pairs (x, y), such as {(2, 5), (4, 9), (-3, 7), (2, 0)} or {(2, 3), (5, -2)}. A function is a special type of relation in which each x-value is assigned a unique y-value. So in the two examples given above, the first relation is NOT a function because the x-value of 2 is assigned two different y-values: 5 and 0. The second example above is a relation, since each x-value given (i.e., 2 and 5) is only assigned to one y-value (i.e., 3 and -2, respectively). Two additional examples: {(0, 5), (1, 3), (1, 8), (4, -2)} is NOT a function, because the x-value of 1 is assigned to two different y-values. {(0, 3), (1, 4), (3, -2), (4, 7), (5, 0)} is a function, because there is no x-value that is assigned to more than one y-value. When graphed in the Cartesian plane, you can determine if a relation is a function or not by the "vertical line test", which says that if there is any place where a vertical line can be drawn that will pass through the graph more than once, then that relation is NOT a function. But if every vertical line that can possibly be drawn only passes through the relation at most once, then that relation is a function.
Which ordered pair could you remove from the relation 1 0 1 3 2 2 2 3 3 1 so that it becomes a function?
Removing one pair is not enough to make it a function. You need to remove one of the pairs starting with 1 as well as a pair starting with 2.
Is (6 8) (-4 -1) (2 3) a function or a relation?
It is both.
How do you determine if you are given a set of ordered pairs that represent a function?
A relation is a set of ordered pairs.A function is a relation such that for each element there is one and only one second element.Example:{(1, 2), (4, 3), (6, 1), (5, 2)}This is a function because every ordered pair has a different first element.Example:{(1, 2), (5, 6), (7, 2), (1, 3)}This is a relation but not a function because when the first element is 1, the second element can be either 2 or 3.
Is (3 6) (1 6) (5 6) (8 6) a function or relation?
It is both.
What is the domain of this relation (-3 0) (-2 -5) (-2 6) (3 7) (0 -17)?
The domain is the set {-3, -2, 0, 3}. Note that because -2 is mapped to -5 as well as 6, this relationship is not a function.
What is the function for this function table x -3 -2 0 1 2 y 9 4 0 1 4?
Y = x2
What is the relationship between 5 0 4 1 3 2 2 3 4 1 0 5?
The relation ship betwee them that Un+Un+1=5
