There is, because {0} has one element, 0. The set {0} therefore can have infinite sets, providing that, all sets are either null or has one element, 0.
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Because every set is a subset of itself. A proper subset cannot, however, be a proper subset of itself.
It isn't. The empty set is a subset - but not a proper subset - of the empty set.
-28 belongs to: Integers, which is a subset of rationals, which is a subset of reals, which is a subset of complex numbers.
Since B is a subset of A, all elements of B are in A.If the elements of B are deleted, then B is an empty set, and also it is a subset of A, moreover B is a proper subset of A.
This problem can be modeled and tested quite easily. Set A can be [X,Y], subset B [X,Y], and subset A [X,Y]. Therefore A and B are equivalent.