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What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
An equation of a nonlinear function and provide two inputs to evaluate?
y=x2+3 x1=1 x2=2 y(x1) = 1*1+3 = 4 y(x2) = 2*2+3 = 7 x2/x1 = 2, While y2/y1 = 7/4 !=2, and thus the function is nonlinear.
What is the x-intercept of Y equals x2-3x plus 2?
1 and 2
What is the effect on the graph of the equation y equals x2 plus 1 when it is changed to y equals x2 plus 5?
It keeps the same shape and size, but the whole thing rises four units on the paper, as if by magic.
How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
Is y equals x2 plus 1 a function?
Yes. Think of y as being a function of x. y = f(x) = x2 + 1
Y equals x2 plus 2x plus 1?
y = x2 + 2x + 1zeros are:0 = x2 + 2x + 10 = (x + 1)(x + 1)0 = (x + 1)2x = -1So that the graph of the function y = x + 2x + 1 touches the x-axis at x = -1.
What is y equals x2 plus 2x plus 1 on a graph?
Interpreting that function as y=x2+2x+1, the graph of this function would be a parabola that opens upward. It would be equivalent to y=(x+1)2. Its vertex would be at (-1,0) and this vertex would be the parabola's only zero.
What is the x-coordinant of the vertex in the function y equals x2 plus 14 plus 21?
y = x2 + 14x + 21 a = 1, b = 14 x = -b/2a = -14/2*1 = -7
Is x2 plus 5x a function?
No. x2+5x is a polynomial, an algebraic expression or a formula, but it is not a function. It could be used to help define a function. {(x,y) | y = x2 + 5x , x any real number} is a function
What are the solutions for x when y equals 0 in the quadratic function y equals x2 plus x?
y = x2 + x = 0 x (X + 1) = 0 x = 0 is one solution x = -1 is the other
Sum of series 1 plus x2 plus x4.....plus xn?
(xn+2-1)/(x2-1)ExplanationLet Y=1+x2+x4+...+xn. Now notice that:Y=1+x2+x4+...+xn=x2(1+x2+x4+...+xn-2)+1Y+xn+2=x2(1+x2+x4+...+xn-2+xn)+1Y+xn+2=x2*Y+1Y+xn+2-x2*Y=1Y-x2*Y=1-xn+2Y(1-x2)=1-xn+2Y=(1-xn+2)/(1-x2)=(xn+2-1)/(x2-1)
What is the axis of symmetry for the function - y equals x squared plus 2x plus 1?
y=x2+2x+1 -b -2 2a= 2= -1 = axis of symmetry is negative one.
What is the range of the function y equals -x2 plus 1?
y = -x2 + 1 This function describes a parabola that opens downward. To find the top of it's range, you need to find it's focal point. You can do that very easily by taking the derivative of the equation and solving it for 0: y = -x2 + 1 ∴ y' = -2x let y' = 0: 0 = -2x ∴ x = 0 Now you can calculate the y value at that point: y = -02 + 1 ∴ y = 1 So that function describes an upside down parabola whose peak is at the point {0, 1}. It's range then is: {y | y ∈ ℜ, y ≤ 1}
What is the x coordinant of the vertex in the function y equals x2 plus 14 plus 21?
y = x2 + 14x + 21; a = 1, b = 14, c = 21 x-coordinate = -b/2a = -14/2 = -7 if it is y = x2 + 14 + 21, the x-coordinate is zero, since b = 0.
Is equation is x2 plus y2 equals 1 what is the circles radius?
Proper form first. X2 + Y2 = 1 Y2 = 1 - X2 Y = (+/-) sqrt(1 - X2) -------------------------- zero out the X Y = (+/-) sqrt(1 - 02) Y = 1 ----------------the radius of this circle
How do you derivative x plus y - 1 equals ln x2 plus y2?
There are several steps involved in how one can solve the derivative x plus y - 1 equals x2 plus y2. The final answer to this math problem is y'(x) = (1-2 x)/(2 y-1).
