0
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared".
There is no equation (nor inequality) in the question, not even a valid expression. So there is nothing that can be solved.
What else can I help you with?
What is a is a trinomial expression?
aX^2 + bX + c
What is an Quadratic in form?
Ax^2 + bx + c = 0
What is standard the form of a quadratic equation?
Ax 2+Bx+c=0
How do you find the x-intercepts of this function parabola?
Solve the quadratic equation.If y = ax^2+bx+c then the intercepts arex = [-b +/- sqrt(b^2 - 4ac)]/(2a).The solutions are real if and only if b^2 >= 4ac
How do you complete the square for negative quadratics I.e. in the form -ax2 bx c?
Without using complex numbers, which is a bad idea, you can't. But you can do something which is almost as good: instead of dealing with -ax^2+bx+c, you can take -(ax^2-bx-c), and then complete the square for the inside quadratic. This will give you something like -((rx+s)^2+t), which is usually good enough. For example, if you're completing the square in order to solve a quadratic equation, the sign on the outside doesn't matter: if -((rx+s)^2+t)=0 then (rx+s)^2+t=0 as well (because the negative of 0 is 0). A different approach, which is usually more useful, is to factor out the a, regardless of whether it's positive or negative. Then instead of completing the square for ax^2+bx+c, you complete the square for x^2+b/ax+c/a, and multiply the final result by a.
What is the answer of factoring by grouping terms of ax plus 2a plus bx plus 2b?
(x + 2)(a + b)
What is the integral of sin3ycos5ydy?
Best way: Use angle addition. Sin(Ax)Cos(Bx) = (1/2) [sin[sum x] + sin[dif x]], where sum = A+B and dif = A-B To show this, Sin(Ax)Cos(Bx) = (1/2) [sin[(A+B) x] + sin[(A-B) x]] = (1/2) [(sin[Ax]Cos[Bx]+sin[Bx]cos[Ax]) + (sin[Ax]cos[-Bx]+sin[-Bx]cos[Ax])] Using the facts that cos[-k] = cos[k] and sin[-k] = -sin[k], we have: (1/2) [(sin[Ax]Cos[Bx]+sin[Bx]cos[Ax]) + (sin[Ax]cos[-Bx]+sin[-Bx]cos[Ax])] (1/2) [(sin[Ax]Cos[Bx]+sin[Bx]cos[Ax]) + (sin[Ax]cos[Bx]-sin[Bx]cos[Ax])] (1/2) 2sin[Ax]Cos[Bx] sin[Ax]Cos[Bx] So, Int[Sin(3y)Cos(5y)dy] = (1/2)Int[Sin(8y)-Sin(2y)dy] = (-1/16) Cos[8y] +1/4 Cos[2y] + C You would get the same result if you used integration by parts twice and played around with trig identities.
How do you solve for roots in a parabola?
If the equation of the parabola isy = ax^2 + bx + c then the roots are [-b +/- sqrt(b^2-4ac)]/(2a)
What is a is a trinomial expression?
aX^2 + bX + c
What is an Quadratic in form?
Ax^2 + bx + c = 0
Ax2 bx c0?
ax^2+bx+c=0 is the standard form of a quadratic function.
How do you solve the equation ax bxc?
The expression you presented is not an equation. Do you mean ax2 + bx = c? Do you mean to solve it for x? I'm assuming that's the case, but you need to be more clear on your question. To solve for x then, the technique to use is called completing the square: ax2 + bx = c Multiply both sides by a: a2x2 + abx = ac Add the square of b/2 to both sides: a2x2 + abx + (b/2)2 = ac + (b/2)2 We now have a perfect square on the left, simplify: (ax + b/2)2 = ac + b2 / 4 (ax + b/2)2 = (4ac + b2) / 4 And now solve for x: ax + b/2 = ±[(4ac + b2) / 4]1/2 ax + b/2 = ± √(4ac + b2) / 2 ax = [-b ± √(4ac + b2)] / 2 x = [-b ± √(4ac + b2)] / 2a
Find the x value for point C such that AC and BC form a 23 ratio.?
It is (2*Ax + 3*Bx)/5 where Ax and Bx are the x coordinates of A and B.
What is the degree of a quadratic inequality?
The degree of a quadratic inequality is 2. This is because it involves a quadratic expression, typically in the form (ax^2 + bx + c ), where (a), (b), and (c) are constants and (a \neq 0). The inequality can be expressed as (ax^2 + bx + c < 0), (ax^2 + bx + c > 0), or similar forms, all of which are characterized by the highest exponent of the variable being 2.
8086 program for addition of two 64 bit numbers?
8150
What is standard the form of a quadratic equation?
Ax 2+Bx+c=0
How do you write a parabola in standard form?
y = ax^2 + bx + c
