s=5 f+s=? Substitute 5 in for s.Substitute 1 in for f.f+s=f+5f=11+5 ={6}
+6
-2
To integrate e^(-2x)dx, you need to take a u substitution. u=-2x du=-2dx Since the original integral does not have a -2 in it, you need to divide to get the dx alone. -(1/2)du=dx Since the integral of e^x is still e^x, you get: y = -(1/2)e^(-2x) Well, that was one method. I usually solve easier functions like this by thinking how the function looked like before it was differentiated. I let f(x) stand for the given function and F(x) stand for the primitive function; the function we had before differentiation (the integrated function). f(x)= e-2x <-- our given function F(x)= e-2x/-2 <-- our integrated function Evidence: F'(x)= -2e-2x/-2 = e-2x = f(x) Q.E.D It's as simple as that.
T,e,t,t,f,f,s,s,e
If: 5f+3 = 28 then f = 5 because (5*5)+3 = 28
4-5f=64 subtract 4 on both sides to isolate 5f. 4-4 cancels out and 64-4 is 60 -4 -4 -5f=60 divide both sides by -5 to isolate f. -5/-5 cancels out and 60/5 is 12 /-5 /5 f=12 now f is isolated and the solution on the other side is 12! You should now how to solve equations by now unless your mentally retarded btw.
s=5 f+s=? Substitute 5 in for s.Substitute 1 in for f.f+s=f+5f=11+5 ={6}
-6 plus 2f plus 3f equals 29 -6 + 2f + 3f = 29 -6 + 5f = 29 5f = 35 f = 7
It depends on what you mean by "solve". This is the "ambiguous" case so that there are two possible solutions depending on whether F is acute or obtuse. Assuming one or the other, the sine rule will give you angle E and so angle F can be calculated and, from that, side f.
30 + 5f = 120 -30 -30 5f = 90 /5 /5 f = 18 Check: 30 + 5 (18) = 120 30 + 90 = 120 120 = 120
a = F divided by km
5f in mathematical terms means -5 multiplied by 'f',so 5f is 5 whole units-as is 5a or 5x1?
f(x)= 3x+2 x=5f(5)=3(5)+2f(5)=17y=17(5,17)
yup
3-e = 4-f f-e = 4-3 f-e = 1
D E F (hold it for 2 seconds) E D D E F A E F D F G A (Hold it) A A A G E F G G (Hold It) G G G F D E F (Hold It) E D D E F A E F D I hope this was accurate. I hope I helped :) (The F's are the normal F's.) Ex: C (High) B A G F <---- E D C (Low)