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Solve the equation 7cosx equals 3sinx for 0dgrees less than x less than or equal to 360degrees?
Oh, dude, we're getting all mathy up in here! So, to solve this bad boy, you can divide both sides by sin(x) to get tan(x) = 7/3. Then, you can take the arctan of both sides to find x. Just make sure you're in the right quadrant, like, don't go wandering off into negative angles, man.
What else can I help you with?
What is the maximum and minimum of y equals 3sinx?
+3 and -3
What is the indefinite integral of 3sinx-5cosx?
8
What is the indefinite integral of 3sinx 5cosx?
With respect to x, this integral is (-15/2) cos2x + C.
What is the derivative of y equals -3xsinx - 1.5x to the 2 plus 5x when x equals pi?
y=-3x*sinx-1.5x2+5x, when x=πy'=d/dx(-3x*sinx)-d/dx(1.5x2)+d/dx(5x)y'=(-3x*d/dx(sinx)+sinx*d/dx(-3x))-d/dx(1.5x2)+d/dx(5x)y'=(-3x*cosx+sinx(-3))-d/dx(1.5x2)+d/dx(5x)y'=(-3x*cosx-3sinx)-3x+5y'=-3x*cosx-3sinx-3x+5 is the derivative at any point of that equation, now you only have to plug in π for xy'(π)=-3π*cosπ-3sinπ-3π+5y'(π)=-3π*(-1)-3(0)-3π+5y'(π)=3π-3π+5y'(π)=5
What is the range of y 3sinx 3?
If y = 3sin(x)3, and x has no limit, then y has a range of -3 to 3.
What is the derivative of cos-13 5cosx5 3cosx?
d(cos−13 + 5cosx5 + 3cosx)/dx = −1/2(1−32) − 25x4sinx5 − 3sinx
What is the maximum value of 3sinx plus 2?
The sine function (sin x) can only have values in the range between 1 and -1. Perhaps you can work it out from there.
What is the maximum value of y equals 3sinx plus 2?
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
What is formula for cos3x?
looks like the exponents did not show up, in the first it should be 4 cosine cubed x - 3cosx and the sin 3x should be 3sinx - 4sine cubed x
Solve 2sinx-sin3x equals 0?
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
How do you evaluate this limit Algebraically limit as x approaches 0 of 3sinx divided by x-2tanx without using Lhospital rule?
sinx = sin0 = 0 tanx = tan0 = 0 you have 0/0 by you limit conditions
How do you express sin 3x as a polynom with sin x using the De Moivre formula?
According to de Moivre's formula, cos3x + isin3x = (cosx + isinx)3 = cos3x + 3cos2x*isinx + 3cosx*i2sin2x + i3sin3x Comparing the imaginary parts, isin3x = 3cos2x*isinx + i3sin3x so that sin3x = 3cos2x*sinx - sin3x = 3*(1-sin2x)sinx - sin3x = 3sinx - 4sin3x
