The sine function (sin x) can only have values in the range between 1 and -1. Perhaps you can work it out from there.
2sinx - sin3x = 0 2sinx - 3sinx + 4sin3x = 0 4sin3x - sinx = 0 sinx(4sin2x - 1) = 0 sinx*(2sinx - 1)(2sinx + 1) = 0 so sinx = 0 or sinx = -1/2 or sinx = 1/2 It is not possible to go any further since the domain for x is not defined.
Tan(3a_)(sqrt(2) / 2 )(sqrt(2)/2) + 0.5 Tan(3a) ( 2/4) + 1/2 Tan(3a) ( 1/2 + 1/2 ) Sin(3a) (1) / 2Cos(3a) + 1/2 Without beinf equated to anything this will not go any further.
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The exact value of 60 degrees would be 1/2. This is a math problem.
It is 3/13 - 2/13*i
The only variable on the right hand side is sin(x). The maximum value of sin(x) is 1. So, the max value of 3sin(x) is 3*1 = 3 and so, the max value of 3sin(x) + 2 is 3+2 = 5.
With respect to x, this integral is (-15/2) cos2x + C.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
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The maximum value for m in a 3d orbital is 2. This corresponds to the three possible orientations of the orbital along the x, y, and z axes.
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The value of 1 plus the square root of 2 is approximately 2.41.
2 + 3A + 9A = 2 + 12AThe numerical value depends on the value of 'A'.It changes whenever 'A' changes.
What is the abs value of X plus 2 less than 9?
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).
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6.