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What is the solution set of x2 y2 26 and x y 6?
If you mean: x squared + y squared = 26 and x + y = 6 Then it works out that: y = 1 or 5 and therefore x = 5 or 1
How do you solve y-6-2(x 2)?
If you mean: y-6-2(x+2) then it can be simplified to y-2x-10
Y equals b plus x plus x2?
y=b+x+x^2 This is a quadratic equation. The graph is a parabola. The quadratic equation formula or factoring can be used to solve this.
Factorise x2 minus y2 plus 9x minus 9y?
x2 - y2 + 9x - 9y =(x2 + 9x) - (y2 + 9y) =x(x + 9) - y(y + 9)================================Another way to go after it:x2 - y2 + 9x - 9y =(x2 - y2) + 9x - 9y =(x + y) (x - y) + 9 (x - y) =(x + y + 9) (x - y)
How do you factor x6 - y6?
(x - y)(x + y)(x2 - xy + y2)(x2 + xy + y2)
How do you solve this equation for x - y equals x - x2?
You cannot, in general, solve one equation with two unknown variables. x - y = x - x2 Subtract x from both sides: - y = - x2 Change signs: y = x2 And that is as far as you can go.
How do you solve the factoring different of two square?
X2 - Y2 = (X + Y)(X - Y)
What are the solutions for y equals x squared and y equals x plus 6?
if: y = x2 y = x + 6 then x2 = x + 6 => x2 - x - 6 =0 => (x - 3)(x + 2) = 0 => x = 3 or -2 => y = 9 or 4 respectively, ie the points (3, 9) and (-2, 4).
Solution set of y equals x2 - x - 6?
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What are 2 integers whose product is -24 and whose sum is 6?
There are two numbers that meet those conditions, but they are not integers. You can work this out by taking the two statements and expressing them as equations, then using substitution to solve. We're told that we have two numbers that add up to six and that multiply to make -24. If we call those numbers x and y, we can say: x + y = 6 xy = -24 Now we'll take the first of them, and solve for y: y = 6 - x And substitute it into the latter: x(6 - x) = -24 6x - x2 = -24 x2 - 6x - 24 = 0 We now have a quadratic equation and can solve it this way: x2 - 6x - 24 = 0 x2 - 6x + 9 = 33 (x - 3)2 = 33 x - 3 = ±√33 x = 3 ± √33
What are the points of intersection of the curves y equals x2 -7x plus 8 and y equals -x2 plus 9x -6 showing work?
If: y = x2-7x+8 and y = -x2+9x-6 Then: x2-7x+8 = -x2+9x-6 So: 2x2-16x+14 = 0 => x2-8x+7 = 0 Therefore: x = 1 and x = 7 By substitution: x =1, y = 2 and x = 7, y = 8 Points of intersection: (1, 2) and (7, 8)
How do I solve X squared plus X squared equals?
x2 + x2 = 2x2. Don't be thrown by squares (or other powers). y + y = 2y. Just treat x2 like you treat y. But remember, you can only add together the same powers of x, you cannot add together x and x2 (or other powers of x).
What two numbers add up to make six and multiply to make 7?
Let's call them x and y. x+y=6,xy=7. So, y=6-x and xy=7. We subsitute 6-x for y and get x(6-x)=7. Distribute x. 6x-x2=7. Subtract 7 from both sides. -x2+6x-7=0. Use the Quadratic Formula: x=(-b+or-sqrt(b2-4ac))/2a. Plug in and solve. Your 2 answers are -6+or-sqrt(8)/-2.
What are the solutions for the simultaneous equation y plus 1 equals x and y equals x squared - 6x plus 5?
equation1: y+1 = x => y = x-1 equation 2: y = x2-6x++5 If, x2-6x+5 = x-1 then, x2-7x+6 = 0, solving this quadratic equation, x = 1 or x = 6 Substituting into equation 1: when x = 1, y = 0 and when x = 6, y = 5 Therefore the solutions are: x = 1, y = 0 and x = 6, y = 5
Z2 equals x2 plus y2?
What are we solving here for, Z, X, or Y?If solve for Z then the answer would be z = x + yIf solve for X then the answer would be z = z - yIf solve for Y than the answer would y = z - xHope this help.
Convert x2 plus y2 equals 2x?
What do you want to convert it to? x2 + y2 = 2x If you want to solve for y: x2 + y2 = 2x ∴ y2 = 2x - x2 ∴ y = (2x - x2)1/2 If you want to solve for x: x2 + y2 = 2x ∴ x2 - 2x = -y2 ∴ x2 - 2x + 1 = 1 - y2 ∴ (x - 1)2 = 1 - y2 ∴ x - 1 = ±(1 - y2)1/2 ∴ x = 1 ± (1 - y2)1/2
How do you solve x plus 5 multiply by y-x equal 3?
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