The substitute of F in the equation F times 2 X times 3 X would be 0. This is taught in math.
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What answer is this f(x)=3x+10 and g(x)=2x-4 find (f+g)(x)?
find f'(x) and f '(c)f(x) = (x^3-3x)(2x^2+3x+5
If f(x)=2z^2+5 and g(x)=x^2-2, fine (f-g)(x)
3x+5
if f(x) = 3x - 10, then whatever is put (substituted) for x in the "f(x)" bit is substituted for x in the "3x - 10" bit. Thus f(2a) = 3(2a) - 10 = 6a - 10.