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What is the percent error of a estimated measurement of 0.229 cm if the actual value is 0.225 cm?

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Johncarlos Aguilar R...

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6mo ago
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12y ago

.229/.225 = 1.0178

percent error = (1.0178 - 1) times 100 to get to percent

= .0178 x 100 = 1.78%

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Q: What is the percentage error of a length measurement of 0.229 cm if the correct value is 0.225 cm?
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