BC and DE
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
It is a tranversal.
The coordinates of all points in the coordinate plane consist of ordered pairs of numbers.
All of the points on a perpendicular bisector are equidistant from the endpoints of the segment.
You have points A, B, and C. Using a compass and straight edge, find a perpendicular bisector of AB (that is, a line that is perpendicular to AB and intersects AB at the midpoint of AB. Next, find a perpendicular bisector of BC. The two lines you found will meet at the center of the circle.
To name an angle bisector, you typically use the vertex of the angle and the points where the bisector intersects the sides of the angle. For example, if you have an angle formed by points A, B, and C, where B is the vertex, and the bisector intersects the sides at points D and E, you can name the angle bisector as segment BD or segment BE, depending on which side you refer to. It’s also common to denote the angle bisector with the symbol for bisector, such as ( \overline{BD} ) or ( \overline{BE} ).
Given a straight line joining the points A and B, the perpendicular bisector is a straight line that passes through the mid-point of AB and is perpendicular to AB.
The perpendicular bisector of the straight line joining the two points.
The locus point is the perpendicular bisector of AB. The locus point is the perpendicular bisector of AB.
A perpendicular line is one that is at right angle to another - usually to a horizontal line. A perpendicular bisector is a line which is perpendicular to the line segment joining two identified points and which divides that segment in two.
The perpendicular bisector of the line segment connecting points R and S is a line that is perpendicular to the segment at its midpoint. Any point on this line is equidistant from R and S, meaning the distance from any point on the bisector to R is the same as the distance to S. This property makes the perpendicular bisector a crucial concept in geometry, particularly in triangle construction and circle definition.
The answer letters always rearrange so here are the answers point H is the midpoint of FG line t intersects FG at a right angle Line T is perpendicular to FG
Yes, in a circle, the perpendicular bisector of a chord does indeed pass through the center of the circle. This is because the perpendicular bisector of a chord divides it into two equal segments and is equidistant from the endpoints of the chord. Since the center of the circle is the point that is equidistant from all points on the circle, it must lie on the perpendicular bisector. Thus, any chord's perpendicular bisector will always intersect the center of the circle.
The perpendicular bisector of the line joining the two points.
Adjust a compass so the distance between the point and the pencil is more than half of the length of the segment. With the point at one end of the segment draw an arc that intersects the segment. Without adjusting the compass, with the point at the other end of the segment draw an arc that intersects the first arc at two places. The line that includes those two intersecting points is the perpendicular bisector.