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Earn +20 ptsQ: The line y=2x+5 intersects the curve y+xy=5 at the points a and b. find the coordinates of the point where the perpendicular bisector of line a and b intersects the line y=x?
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What is the perpendicular bisector equation to the line segment of -1 -6 and 5 -8?
Points: (-1, -6) and (5, -8) Midpoint: (2, -7) Perpendicular slope: 3 Perpendicular bisector equation: y = 3x -13
How do you find the midpoint the slope the perpendicular slope and the equation for the perpendicular bisector of the line segment joining the points of 3 5 and 7 7?
Midpoint = (3+7)/2, (5+7)/2 = (5, 6) Slope of line segment = 7-5 divided by 7-3 = 2/4 = 1/2 Slope of the perpendicular = -2 Equation of the perpendicular bisector: y-y1 = m(x-x1) y-6 =-2(x-5) y = -2x+10+6 Equation of the perpendicular bisector is: y = -2x+16
What is the perpendicular bisector equation joining the line segment of -2 plus 5 and -8 -3 giving brief details?
Points: (-2, 5) and (-8, -3) Midpoint: (-5, 1) Slope: 4/3 Perpendicular slope: -3/4 Use: y-1 = -3/4(x--5) Bisector equation: y = -3/4x-11/4 or as 3x+4y+11 = 0
What is a line that intersects two or more coplanar lines at different points?
It is a tranversal.
Describe the coordinates of all points in all the quadrants?
The coordinates of all points in the coordinate plane consist of ordered pairs of numbers.
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