Approximately 5.2115 and 9.2115
the width is 1 and the length is 2. 2 multipleyed by 1 equals 2...
Let the width be (x-3) and the length be x: width*length = area (x-3)*x = 340 square inches x2-3x-340 = 0 Solving the above quadratic equation works out as: x = -17 or x = 20 it must be the latter because dimensions can't be negative. Therefore: length = 20 inches and width = 17 inches Check: 20*17 = 340 square inches
Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".
the length of a rectangle is 4 centimeters less than three times the width. the perimetreris 64 centimeters. find the width and length.
20 feet long by 16 feet wideLet the width be x-4 and the length be x:(x-4)*x = 320x2-4x-320 = 0Solving the above quadratic equation works out as:x = -16 or x = 20 so it must be the latter because dimensions can't be negative.Answer: width = 16 feet
width=16 and length=20
The width is 16 feet
From the statement of the problem, if w is the width, the area is 2w2 , the product of the width and the length, which is stated to be twice the width. Since 2w2 must be less than 50, w2 < 25, and the width must be less than 5 meters.
Easy. Width = 2ft, Length = 4 ft, therefore the Area = 8 ft.
the width is 1 and the length is 2. 2 multipleyed by 1 equals 2...
Factors of 28 include 7 x 4. 7 is 1 less than twice 4...
I assume you mean that the length is less than four times the width. Here is the outline. First assume, for simplicity, that the length is EQUAL to 4 times the width. Write two equatios for that - one for the perimeter, one for the area. Solve it, and find the corresponding area. That's basically the minimum area. At the other extreme, make the length equal to the width, and solve again. That would be the maximum area.
length is 3 and width is 9
4
The width is 16 feet and the length is 20 feet and so 16*20 = 320 square feet
Its width is 13 feet and 13*19 = 247 square feet
this is a funky question... 8x10 kilometers